Question

In 2 hours, a train covers 130km. Travelling at the same speed, what distance would the train cover in $5$ hours.

Answer 1

Hint: First, the given problem is based on the quantity of speed, distance, and time. The relation between them can be expressed as $S = \dfrac{D}{T}$ where S is the speed, T is the time taken and D is the distance covered.
Since the train is traveling at the same speed we can also solve this using the unitary method. The requirement is what distance the train would cover is five hours.

Complete step-by-step solution:
Since from the given that we have, $2$ hours a train covers $130km$. Which can be represented mathematically as $2h = 130km$
Now we will find the train cover distance for the one hour, so that it will be easy to solve further.
Let us divide the values using the division operation by the number two we have $\dfrac{2}{2}h = \dfrac{{130}}{2}km$
Further solving we get $1h = 65km$ in one hour the train travels at a distance of sixty-five kilometers.
Hence to find the train cover in $5$ hours we will multiply it into the $5$ with $1h = 65km$
Then we have $5 \times 1h = 5 \times 65km \Rightarrow 5h = 325km$
Hence the train would cover $325km$ distance in $5$ hours.

Note: The operations which we used to solve the problem are multiplication and division operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$ is called the multiplicand and the number $7$is called the multiplier. Like $5 \times 1h = 5 \times 65km \Rightarrow 5h = 325km$
The process of the inverse of the multiplication method is called division. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $\dfrac{2}{2}h = \dfrac{{130}}{2}km \Rightarrow 1h = 65km$