If \[y = {x^n}\], then the ratio of relative error in \[y\] and \[x\] is
A) \[1:1\]
B) \[2:1\]
C) \[1:n\]
D) \[n:1\]
Answer
600k+ views
Hint: Before finding the relative error at first, we have to find out the approximate error in terms of \[x\] and \[y\].
By using the approximate error, we can find the relative error.
The relative error gives an indication of how good measurement is relative to the size of the object being measured.
We know that; in Mathematics, differentiation can be defined as a derivative of a function with respect to an independent variable. Differentiation, in calculus, can be applied to measure the function per unit change in the independent variable.
Complete step-by-step answer:
It is given that; \[y = {x^n}\]
We have to find the ratio of relative error in \[y\] and \[x\].
We have,
\[y = {x^n}\]
Differentiate with respect to \[x\] we get,
$\Rightarrow$\[\dfrac{{dy}}{{dx}} = n{x^{n - 1}}\]… (1)
Approximate error in \[y\] is \[dy = \left( {\dfrac{{dy}}{{dx}}} \right)\Delta x\]
Substitute the values from (1) we get,
$\Rightarrow$\[dy = n{x^{n - 1}}\Delta x\]
So, relative error in \[y\] is \[\dfrac{{dy}}{y} = \dfrac{n}{x}\Delta x\]
Approximate error in \[x\] is \[dx = \left( {\dfrac{{dx}}{{dy}}} \right)\Delta y\]
Simplifying we get,
$\Rightarrow$\[dx = \left( {\dfrac{{\dfrac{1}{1}}}{{\dfrac{{dy}}{{dx}}}}} \right)\Delta y\]
Substitute the values from (1) we get,
$\Rightarrow$\[dx = \dfrac{1}{{n{x^{n - 1}}}}\Delta y\]
So, relative error in \[x\] is \[\dfrac{{dx}}{x} = \dfrac{1}{{n{x^n}}}\Delta y\]
Required ratio \[ = \dfrac{{\dfrac{n}{x}\Delta x}}{{\dfrac{1}{{n{x^n}}}\Delta y}}\]
Simplifying we get,
Required ratio \[ = {n^2}{x^{n - 1}}\dfrac{{\Delta x}}{{\Delta y}}\]
Simplifying again we get,
Required ratio \[ = \dfrac{n}{1}\]
So, the ratio of relative error in \[y\] and \[x\] is \[n:1\].
Hence, the correct option is D) \[n:1\].
Note: The relative error is defined as the ratio of the absolute error of the measurement to the actual measurement. Using this method, we can determine the magnitude of the absolute error in terms of the actual size of the measurement.
Absolute error is the difference between measured or inferred value and the actual value of a quantity. The absolute error is inadequate due to the fact that it does not give any details regarding the importance of the error.
By using the approximate error, we can find the relative error.
The relative error gives an indication of how good measurement is relative to the size of the object being measured.
We know that; in Mathematics, differentiation can be defined as a derivative of a function with respect to an independent variable. Differentiation, in calculus, can be applied to measure the function per unit change in the independent variable.
Complete step-by-step answer:
It is given that; \[y = {x^n}\]
We have to find the ratio of relative error in \[y\] and \[x\].
We have,
\[y = {x^n}\]
Differentiate with respect to \[x\] we get,
$\Rightarrow$\[\dfrac{{dy}}{{dx}} = n{x^{n - 1}}\]… (1)
Approximate error in \[y\] is \[dy = \left( {\dfrac{{dy}}{{dx}}} \right)\Delta x\]
Substitute the values from (1) we get,
$\Rightarrow$\[dy = n{x^{n - 1}}\Delta x\]
So, relative error in \[y\] is \[\dfrac{{dy}}{y} = \dfrac{n}{x}\Delta x\]
Approximate error in \[x\] is \[dx = \left( {\dfrac{{dx}}{{dy}}} \right)\Delta y\]
Simplifying we get,
$\Rightarrow$\[dx = \left( {\dfrac{{\dfrac{1}{1}}}{{\dfrac{{dy}}{{dx}}}}} \right)\Delta y\]
Substitute the values from (1) we get,
$\Rightarrow$\[dx = \dfrac{1}{{n{x^{n - 1}}}}\Delta y\]
So, relative error in \[x\] is \[\dfrac{{dx}}{x} = \dfrac{1}{{n{x^n}}}\Delta y\]
Required ratio \[ = \dfrac{{\dfrac{n}{x}\Delta x}}{{\dfrac{1}{{n{x^n}}}\Delta y}}\]
Simplifying we get,
Required ratio \[ = {n^2}{x^{n - 1}}\dfrac{{\Delta x}}{{\Delta y}}\]
Simplifying again we get,
Required ratio \[ = \dfrac{n}{1}\]
So, the ratio of relative error in \[y\] and \[x\] is \[n:1\].
Hence, the correct option is D) \[n:1\].
Note: The relative error is defined as the ratio of the absolute error of the measurement to the actual measurement. Using this method, we can determine the magnitude of the absolute error in terms of the actual size of the measurement.
Absolute error is the difference between measured or inferred value and the actual value of a quantity. The absolute error is inadequate due to the fact that it does not give any details regarding the importance of the error.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

Why should a magnesium ribbon be cleaned before burning class 12 chemistry CBSE

