QUESTION

# ${\text{If }}x\cos {60^0} - y\cos {0^0} = 3 \\ 4x\sin {360^0} - y\cot {45^0} = 2 \\$Then what is the value of x?${\text{A}}{\text{. - 1}} \\ {\text{B}}{\text{. 0}} \\ {\text{C}}{\text{. 1}} \\ {\text{D}}{\text{. 2}} \\$

$x\cos {60^0} - y\cos {0^0} = 3 \\ 4x\sin {360^0} - y\cot {45^0} = 2 \\$
$\ cos {60^0} = \dfrac{1}{2},\cos {0^0} = 1 \\ \sin {360^0} = 0,\cot {45^0} = 1 \\$
$\dfrac{x}{2} - y = 3 \\ 0 - y = 2 \\$