Answer
Verified
419.4k+ views
Hint: For solving this type of question we always have to frame the equation in such a way that it will follow the formula which is given by $ {\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab $ . In this we will add $ 2 $ both the sides and framing the equation, we get the value for $ {x^3} + \dfrac{1}{{{x^3}}} $ .
Formula used:
The algebraic formula will be given by
$ {\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab $
Here, $ a\& b $ will be the variables.
Complete step-by-step answer:
We have the equation given as $ {x^4} + \dfrac{1}{{{x^4}}} = 194 $
Now on adding both the sides $ 2 $ , we get the equation as
$ \Rightarrow {x^4} + \dfrac{1}{{{x^4}}} + 2 = 194 + 2 $
Now by using the formula, the left side of the equation will be given as
$ \Rightarrow {\left( {{x^2} + \dfrac{1}{{{x^2}}}} \right)^2} = 196 $
By removing the square from the left sides of the equation, we will get the equation as
$ \Rightarrow \left( {{x^2} + \dfrac{1}{{{x^2}}}} \right) = 14 $
Now again adding $ 2 $ both the sides of the equation, we will get
$ \Rightarrow {x^2} + \dfrac{1}{{{x^2}}} + 2 = 14 + 2 $
Again we can see that the left side of the equation is following the formula $ {\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab $
$ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^2} = 16 $
By removing the square from the left sides of the equation, we will get the equation as
$ \Rightarrow x + \dfrac{1}{x} = 4 $ , and we will name it equation $ 1 $
Now for finding the $ {x^3} + \dfrac{1}{{{x^3}}} $ , we will take out the cube root of the equation $ 1 $ .
$ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^3} = {4^3} $
We get,
\[ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^3} = {x^3} + \dfrac{1}{{{x^3}}} + 3\left( {x + \dfrac{1}{x}} \right)\]
And from this, we will get
$ \Rightarrow {4^3} = {x^3} + \dfrac{1}{{{x^3}}} +3 \times 4 $
And on solving and taking the constant term to one side, we get the equation as
$ \Rightarrow {x^3} + \dfrac{1}{{{x^3}}} = 52 $
Hence, the option $ \left( b \right) $ is correct.
So, the correct answer is “Option b”.
Note: Here, in this question, we can see that with the help of the formula we can easily solve this type of question. So the important thing for us will be to memorize the formula and by practice, we will get the knowledge of substituting the formula with the question. Also while solving the question for the long answer question, we should follow each step.
Formula used:
The algebraic formula will be given by
$ {\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab $
Here, $ a\& b $ will be the variables.
Complete step-by-step answer:
We have the equation given as $ {x^4} + \dfrac{1}{{{x^4}}} = 194 $
Now on adding both the sides $ 2 $ , we get the equation as
$ \Rightarrow {x^4} + \dfrac{1}{{{x^4}}} + 2 = 194 + 2 $
Now by using the formula, the left side of the equation will be given as
$ \Rightarrow {\left( {{x^2} + \dfrac{1}{{{x^2}}}} \right)^2} = 196 $
By removing the square from the left sides of the equation, we will get the equation as
$ \Rightarrow \left( {{x^2} + \dfrac{1}{{{x^2}}}} \right) = 14 $
Now again adding $ 2 $ both the sides of the equation, we will get
$ \Rightarrow {x^2} + \dfrac{1}{{{x^2}}} + 2 = 14 + 2 $
Again we can see that the left side of the equation is following the formula $ {\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab $
$ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^2} = 16 $
By removing the square from the left sides of the equation, we will get the equation as
$ \Rightarrow x + \dfrac{1}{x} = 4 $ , and we will name it equation $ 1 $
Now for finding the $ {x^3} + \dfrac{1}{{{x^3}}} $ , we will take out the cube root of the equation $ 1 $ .
$ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^3} = {4^3} $
We get,
\[ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^3} = {x^3} + \dfrac{1}{{{x^3}}} + 3\left( {x + \dfrac{1}{x}} \right)\]
And from this, we will get
$ \Rightarrow {4^3} = {x^3} + \dfrac{1}{{{x^3}}} +3 \times 4 $
And on solving and taking the constant term to one side, we get the equation as
$ \Rightarrow {x^3} + \dfrac{1}{{{x^3}}} = 52 $
Hence, the option $ \left( b \right) $ is correct.
So, the correct answer is “Option b”.
Note: Here, in this question, we can see that with the help of the formula we can easily solve this type of question. So the important thing for us will be to memorize the formula and by practice, we will get the knowledge of substituting the formula with the question. Also while solving the question for the long answer question, we should follow each step.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE