If x + y + z = 1, xy + yz + zx = -1 and xyz = -1, find the value of ${x^3} + {y^3} + {z^3}$.
Answer
592.2k+ views
Hint:
The value of the required expression can be found by using the expansion of ${x^3} + {y^3} + {z^3} - 3xyz$. We can obtain the required expression by substituting the values of the terms given in the expansion.
Complete step by step solution:
The expression, ${x^3} + {y^3} + {z^3}$occurs in the expansion of the formula ${x^3} + {y^3} + {z^3} - 3xyz$, so we will use this expansion to find out the value of the required expression.
${x^3} + {y^3} + {z^3} - 3xyz = \left( {x + y + z} \right)\left( {{x^2} + {y^2} + {z^2} - xy - yz - zx} \right)$ …equation (1)
On rearranging the terms in equation (1), we obtain,
${x^3} + {y^3} + {z^3} = \left( {x + y + z} \right)\left( {{x^2} + {y^2} + {z^2} - xy - yz - zx} \right) + 3xyz$ …equation (2)
We now substitute the values of (x + y + z), (xy + yz + zx) and xyz in equation (2), we get,
${x^3} + {y^3} + {z^3} = 1\left[ {{x^2} + {y^2} + {z^2} - \left( { - 1} \right)} \right] + 3\left( { - 1} \right) = {x^2} + {y^2} + {z^2} - 2$
$ \Rightarrow {x^3} + {y^3} + {z^3} = {x^2} + {y^2} + {z^2} - 2$ …equation (3)
But, we need the value of ${x^2} + {y^2} + {z^2}$ in order to obtain the value of the required expression. The term ${x^2} + {y^2} + {z^2}$ can be found in the expansion of ${\left( {x + y + z} \right)^2}$.
${\left( {x + y + z} \right)^2} = {x^2} + {y^2} + {z^2} + 2\left( {xy + yz + zx} \right)$ …equation (4)
On rearranging the terms in equation (4), we obtain,
${x^2} + {y^2} + {z^2} = {\left( {x + y + z} \right)^2} - 2\left( {xy + yz + zx} \right)$ …equation (5)
We find the value of ${x^2} + {y^2} + {z^2}$ by substituting the values of (x + y + z) and (xy + yz + zx) in equation (5)
${x^2} + {y^2} + {z^2} = {\left( 1 \right)^2} - 2\left( { - 1} \right) = 3$
Since we have found the value of ${x^2} + {y^2} + {z^2}$, we can now find the value of the required expression by substituting this value in equation (3),
$ \Rightarrow {x^3} + {y^3} + {z^3} = 3 - 2 = 1$
Hence, the value of ${x^3} + {y^3} + {z^3}$ is 1.
Note:
In questions of this type, we should try using one of such expressions whose expansion contains the required term. It is possible that the expression we need to evaluate is present in more than one expansion. In such cases, we need to use the expansion, which uses the values of the terms given in the question.
The value of the required expression can be found by using the expansion of ${x^3} + {y^3} + {z^3} - 3xyz$. We can obtain the required expression by substituting the values of the terms given in the expansion.
Complete step by step solution:
The expression, ${x^3} + {y^3} + {z^3}$occurs in the expansion of the formula ${x^3} + {y^3} + {z^3} - 3xyz$, so we will use this expansion to find out the value of the required expression.
${x^3} + {y^3} + {z^3} - 3xyz = \left( {x + y + z} \right)\left( {{x^2} + {y^2} + {z^2} - xy - yz - zx} \right)$ …equation (1)
On rearranging the terms in equation (1), we obtain,
${x^3} + {y^3} + {z^3} = \left( {x + y + z} \right)\left( {{x^2} + {y^2} + {z^2} - xy - yz - zx} \right) + 3xyz$ …equation (2)
We now substitute the values of (x + y + z), (xy + yz + zx) and xyz in equation (2), we get,
${x^3} + {y^3} + {z^3} = 1\left[ {{x^2} + {y^2} + {z^2} - \left( { - 1} \right)} \right] + 3\left( { - 1} \right) = {x^2} + {y^2} + {z^2} - 2$
$ \Rightarrow {x^3} + {y^3} + {z^3} = {x^2} + {y^2} + {z^2} - 2$ …equation (3)
But, we need the value of ${x^2} + {y^2} + {z^2}$ in order to obtain the value of the required expression. The term ${x^2} + {y^2} + {z^2}$ can be found in the expansion of ${\left( {x + y + z} \right)^2}$.
${\left( {x + y + z} \right)^2} = {x^2} + {y^2} + {z^2} + 2\left( {xy + yz + zx} \right)$ …equation (4)
On rearranging the terms in equation (4), we obtain,
${x^2} + {y^2} + {z^2} = {\left( {x + y + z} \right)^2} - 2\left( {xy + yz + zx} \right)$ …equation (5)
We find the value of ${x^2} + {y^2} + {z^2}$ by substituting the values of (x + y + z) and (xy + yz + zx) in equation (5)
${x^2} + {y^2} + {z^2} = {\left( 1 \right)^2} - 2\left( { - 1} \right) = 3$
Since we have found the value of ${x^2} + {y^2} + {z^2}$, we can now find the value of the required expression by substituting this value in equation (3),
$ \Rightarrow {x^3} + {y^3} + {z^3} = 3 - 2 = 1$
Hence, the value of ${x^3} + {y^3} + {z^3}$ is 1.
Note:
In questions of this type, we should try using one of such expressions whose expansion contains the required term. It is possible that the expression we need to evaluate is present in more than one expansion. In such cases, we need to use the expansion, which uses the values of the terms given in the question.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

Give me the opposite gender of Duck class 8 english CBSE

Name the states through which the Tropic of Cancer class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Advantages and disadvantages of science

