Question

If the thickness of a pile of 16 cardboard is 44mm, how many cardboards will be there in a pile which is 71.5 cm thick of the same thickness?

Answer 1

Hint: In this question remember to identify the given dimensions and also remember to find the thickness of single cardboard, using this information can help you to find the numbers of cardboard required in a 71.5 cm thick pile.

Complete step-by-step answer:
According to the given information we have 16 cardboard of total thickness 44mm and we have to find the numbers of cardboard required for pile with 71.5 cm thickness
We know that to find the thickness of single cardboard can be given as; \[{\text{Thickness of 1 cardboard }} = {\text{ }}\dfrac{{{\text{Total thickness of numbers of cardboard present}}}}{{{\text{Numbers of cardboard percent}}}}\]
Substituting the given values in the above equation we get
\[{\text{Thickness of 1 cardboard }} = {\text{ }}\dfrac{{44}}{{16}}\]
$ \Rightarrow $\[{\text{Thickness of 1 cardboard }} = {\text{ }}2.75mm\]
Now we have the thickness of 1 cardboard i.e. 2.75 mm
As it is given that thickness of given pile is 71.5 cm which can be written as 715mm
Therefore, to find the numbers of cardboard having thickness 2.75mm each present in the cardboard of thickness 715mm is given as; \[{\text{Numbers of cardboard required }} = {\text{ }}\dfrac{{{\text{Thickness of cardboard}}}}{{{\text{Thickness of 1 cardboard}}}}\]
Substituting the given value in the above equation we get
\[{\text{Numbers of cardboard required }} = {\text{ }}\dfrac{{{\text{715}}}}{{{\text{2}}{\text{.75}}}}\]
$ \Rightarrow $Required numbers of cardboard = 260
Therefore, the required number of cardboard of thickness 2.75mm for a pile with thickness 71.5 cm is 260.

Note: In the above solution we used the method of unitary to find the thickness of single cardboard according to this method to find the value of unit object we require the total value of objects present and the numbers of object then to find the required number of cardboard for given pile we first changed thickness of given pile into millimeter since the given thickness was in cm and the thickness of single cardboard was in mm where 1 cm = 10 mm, than to find the required numbers of cardboard we applied the division operation in the total thickness of pile and the thickness of single cardboard and finally we got the required numbers of cardboard i.e. 260.