Question

If the temperature is ${65^ \circ }F$ outside, what is the temperature in degrees Celsius?

Answer 1

Hint: Fahrenheit and Celsius as the most commonly used scales for the measurement of room, weather and water temperatures. In India we use Celsius scale, in the USA Fahrenheit scale is commonly used. We have to learn the converting factor from one scale to another to solve this question.

Complete answer:
Consider the temperature to be taken as ‘T’ in degree Celsius $^ \circ C$ . To convert this Fahrenheit degree into Celsius is equal to $^ \circ F$ minus 32 times $\dfrac{5}{9}$
Mathematically this can be given as: $T{(^ \circ }C) = [T{(^ \circ }F) - 32] \times \dfrac{5}{9}$
This can also be written as $T{(^ \circ }C) = [T{(^ \circ }F) - 32]/\dfrac{9}{5}$
Simplifying this further $T{(^ \circ }C) = [T{(^ \circ }F) - 32]/1.8$
Now the temperature given to us is ${65^ \circ }F$ . TO convert this into Celsius we’ll have to remember this formula;
$C = (F - 32) \times \dfrac{5}{9}$
Where C is the temperature in Celsius and F is the temperature in Fahrenheit. Substituting the values to find out the value, $C = (65 - 32) \times \dfrac{5}{9}$
$C = (33) \times \dfrac{5}{9} = {18.33^ \circ }C$
Therefore, if the temperature is ${65^ \circ }F$ outside, the temperature in degrees Celsius is ${18.33^ \circ }C$ .
Thus, our required answer is ${18.33^ \circ }C$.

Note:
Now to convert the inverse of this i.e., from Celsius to Fahrenheit, we’ll use the formula $^ \circ F = {(^ \circ }C \times \dfrac{9}{5}) + 32$ . Simplifying the formula further, to easily remember this as: $^ \circ F = {(^ \circ }C \times 2) + 30$ . This is the simplest formula that can be used for the conversion process. If we need to convert Kelvin in Fahrenheit or vice versa, we’ll first convert it into Celsius and then convert into Fahrenheit. For converting Kelvin into Celsius we’ll use the formula $K{ = ^ \circ }C + 273$
The conversion from Fahrenheit to kelvin now will be: $K = (F - 32) \times \dfrac{5}{9} + 273$