If the speed of light were 50% of the present value, by what % the energy released will it decrease?
A. \[100\% \]
B. \[50\% \]
C. \[25\% \]
D. \[75\% \]
Answer
647.4k+ views
Hint: The above problem can be resolved by using Einstein's energy relation. In this relation, the energy is correlated with the velocity of light. And as the final speed of light is 50% of the initial speed, therefore the equations can be solved by taking the ratio of the energies at initial and at final.
Complete step by step answer:
Let E be the initial value of energy released and c be the initial speed of light. As the speed of light is 50%, then the final speed of light is given as,
\[{c_2} = \dfrac{{50}}{{100}}c.............\left( 1 \right)\]
Using the Einstein’s energy relation for the initial and final condition as,
\[\begin{array}{l}
E = m{c^2}....................\left( 2 \right)\\
{E_2} = mc_2^2......................\left( 3 \right)
\end{array}\]
Taking the ratio of equation 3 and 2 as,
\[\begin{array}{l}
\dfrac{{{E_2}}}{E} = \dfrac{{m \times {{\left( {\dfrac{{50}}{{100}}c} \right)}^2}}}{{m{c^2}}}\\
\dfrac{{{E_2}}}{E} = \dfrac{1}{4}\\
{E_2} = \dfrac{{25}}{{100}}E
\end{array}\]
The above result shows that the energy will decrease by 25 % .
Therefore, the energy released will be decreased by 25%
So, the correct answer is “Option C”.
Note:
To solve the given problem, one must be clear with the concept of Einstein's energy equation. According to this equation, the universe is the only comprise of the mass and the energy. Both the mass and the energy can never be destroyed; rather, one is convertible into the another. Therefore, the mathematical relation for this statement is known as the mass-energy equivalence equation. Moreover, the concept of energy conversion is also applied to understand the significance of this equation.
Complete step by step answer:
Let E be the initial value of energy released and c be the initial speed of light. As the speed of light is 50%, then the final speed of light is given as,
\[{c_2} = \dfrac{{50}}{{100}}c.............\left( 1 \right)\]
Using the Einstein’s energy relation for the initial and final condition as,
\[\begin{array}{l}
E = m{c^2}....................\left( 2 \right)\\
{E_2} = mc_2^2......................\left( 3 \right)
\end{array}\]
Taking the ratio of equation 3 and 2 as,
\[\begin{array}{l}
\dfrac{{{E_2}}}{E} = \dfrac{{m \times {{\left( {\dfrac{{50}}{{100}}c} \right)}^2}}}{{m{c^2}}}\\
\dfrac{{{E_2}}}{E} = \dfrac{1}{4}\\
{E_2} = \dfrac{{25}}{{100}}E
\end{array}\]
The above result shows that the energy will decrease by 25 % .
Therefore, the energy released will be decreased by 25%
So, the correct answer is “Option C”.
Note:
To solve the given problem, one must be clear with the concept of Einstein's energy equation. According to this equation, the universe is the only comprise of the mass and the energy. Both the mass and the energy can never be destroyed; rather, one is convertible into the another. Therefore, the mathematical relation for this statement is known as the mass-energy equivalence equation. Moreover, the concept of energy conversion is also applied to understand the significance of this equation.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

The teeth used for biting and cutting food are called class 11 biology CBSE

