Answer
Verified
424.5k+ views
Hint: To solve this problem, we use the formula that profit = selling price – cost price. Here, selling price is the price at which the product is sold after the product is bought at the cost price (as explained, cost price is the price at which a product is bought). Profit percent is given by $\dfrac{\text{Selling Price - Cost Price}}{\text{Cost Price}}\times 100$. We will use this to solve the problem.
Complete step by step answer:
We solve the problem by assuming that the original cost price and selling price be CP and SP. Now, we have the profit (p), we have,
p = SP – CP -- (1)
It is given in the problem that on doubling the selling price, the profit triples, we have,
3p = 2SP – CP -- (2)
Now, we need to find the profit percent given by $\dfrac{\text{Selling Price - Cost Price}}{\text{Cost Price}}\times 100$.
We need to find SP in terms of CP to find the profit percent. We use equations (1) and (2) and solve them to find SP in terms of CP. Firstly, we subtract (1) from (2), we get –
3p-p = SP
SP = 2p -- (A)
Putting this in (1), we get,
p = 2p – CP
CP = p -- (B)
From (A) and (B), we get that SP = 2CP. Now, we put this in the formula of profit percentage given by $\dfrac{\text{Selling Price - Cost Price}}{\text{Cost Price}}\times 100$. We get,
$\left( \dfrac{2CP-CP}{CP} \right)\times 100$ = 100%
Hence, the correct option is (b) 100%.
Note: While solving the equations p = SP – CP and 3p = 2SP – CP (where, p is the profit, SP = selling price and CP = cost price), we see that there are 3 variables for 2 equations. Thus, the equations are explicitly not solvable. However, we are still able to find the required answer since we only have to find the ratio and thus one of the variables cancel out.
Complete step by step answer:
We solve the problem by assuming that the original cost price and selling price be CP and SP. Now, we have the profit (p), we have,
p = SP – CP -- (1)
It is given in the problem that on doubling the selling price, the profit triples, we have,
3p = 2SP – CP -- (2)
Now, we need to find the profit percent given by $\dfrac{\text{Selling Price - Cost Price}}{\text{Cost Price}}\times 100$.
We need to find SP in terms of CP to find the profit percent. We use equations (1) and (2) and solve them to find SP in terms of CP. Firstly, we subtract (1) from (2), we get –
3p-p = SP
SP = 2p -- (A)
Putting this in (1), we get,
p = 2p – CP
CP = p -- (B)
From (A) and (B), we get that SP = 2CP. Now, we put this in the formula of profit percentage given by $\dfrac{\text{Selling Price - Cost Price}}{\text{Cost Price}}\times 100$. We get,
$\left( \dfrac{2CP-CP}{CP} \right)\times 100$ = 100%
Hence, the correct option is (b) 100%.
Note: While solving the equations p = SP – CP and 3p = 2SP – CP (where, p is the profit, SP = selling price and CP = cost price), we see that there are 3 variables for 2 equations. Thus, the equations are explicitly not solvable. However, we are still able to find the required answer since we only have to find the ratio and thus one of the variables cancel out.
Recently Updated Pages
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Find the values of other five trigonometric functions class 10 maths CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
What is the color of ferrous sulphate crystals? How does this color change after heating? Name the products formed on strongly heating ferrous sulphate crystals. What type of chemical reaction occurs in this type of change.
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
What organs are located on the left side of your body class 11 biology CBSE