
If the radius of the circular park is 280 meters, calculate the wire required to cover the four fold boundary of this field.
Answer
606k+ views
Hint: In such kinds of questions we use the formula of circumference of a circle substituting the given radius and thus we get the required wire to cover the four fold boundary of the circular field.
Complete step-by-step answer:
Radius of the field = 280m
We know that the circumference of the circle is $2\pi r$
Also the wire required to cover the boundary is equal to the circumference of the circular field .
Thus to cover it four times the wire required is 4$ \times $ circumference
i.e $4 \times 2\pi r$ , where r = 280 m
Therefore the wire required to cover the circular field four times is $4 \times 2 \times \dfrac{{22}}{7} \times 280$
$ = 8 \times 22 \times 40 = 7040$ m
Note: In such types of questions we have to remember to recall all the properties and formulas of the circle to get the desired result . Also remember to use the value of $\pi $ in fraction in such questions as it mostly gets cancelled out giving us a non decimal result .
Complete step-by-step answer:
Radius of the field = 280m
We know that the circumference of the circle is $2\pi r$
Also the wire required to cover the boundary is equal to the circumference of the circular field .
Thus to cover it four times the wire required is 4$ \times $ circumference
i.e $4 \times 2\pi r$ , where r = 280 m
Therefore the wire required to cover the circular field four times is $4 \times 2 \times \dfrac{{22}}{7} \times 280$
$ = 8 \times 22 \times 40 = 7040$ m
Note: In such types of questions we have to remember to recall all the properties and formulas of the circle to get the desired result . Also remember to use the value of $\pi $ in fraction in such questions as it mostly gets cancelled out giving us a non decimal result .
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