If the dielectric constant of a substance is K =\[\dfrac{4}{3}\] then the electric susceptibility $φ_e$ is:
A. \[\dfrac{1}{3}\]
B. 3
C. \[\dfrac{4}{3}\]
D. \[\dfrac{3}{4}\]
Answer
623.1k+ views
Hint: Since we have to find the Electric susceptibility ( $φ_e$ ). So, using the formula of electric susceptibility we can easily find out the answer.
Where $φ_e$ = K – 1
Complete step-by-step answer:
As given
Dielectric constant (K) = \[\dfrac{4}{3}\]
Where we have to find electric susceptibility ( φe )
So using formula
$φ_e$ = K – 1
so putting the values of Dielectric constant (K) in the equation,
$φ_e$ = \[\dfrac{4}{3}\] - 1 (k = \[\dfrac{4}{3}\])
$φ_e$ = \[\dfrac{{4 - 3}}{3}\]
$φ_e$ = \[\dfrac{1}{3}\]
Note:-
1. Dielectric constant is also known as relative permeability.
2. Relative permeability: It is the ratio of material permeability to the permeability of the free space or vacuum.
Where $φ_e$ = K – 1
Complete step-by-step answer:
As given
Dielectric constant (K) = \[\dfrac{4}{3}\]
Where we have to find electric susceptibility ( φe )
So using formula
$φ_e$ = K – 1
so putting the values of Dielectric constant (K) in the equation,
$φ_e$ = \[\dfrac{4}{3}\] - 1 (k = \[\dfrac{4}{3}\])
$φ_e$ = \[\dfrac{{4 - 3}}{3}\]
$φ_e$ = \[\dfrac{1}{3}\]
Note:-
1. Dielectric constant is also known as relative permeability.
2. Relative permeability: It is the ratio of material permeability to the permeability of the free space or vacuum.
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