
If $p\left( x \right)=x+3$ , then $p\left( x \right)+p\left( -x \right)$ is equal to:
A. 3
B. 2x
C. 0
D. 6
Answer
602.4k+ views
Hint: Here, we are asked to find the value of $p\left( x \right)+p\left( -x \right)$. To solve this first we need to find $p\left( -x \right)$ by substituting ‘-x’ in $p\left( x \right)$ . Then we will add $p\left( x \right)$ and $p\left( -x \right)$ to find the answer.
Complete step-by-step answer:
In this question it is given that, $p\left( x \right)=x+3$ .
Here, we need to find $p\left( x \right)+p\left( -x \right)$ .
To find this first we will find \[p\left( -x \right)\]
Let us take $p\left( x \right)=x+3$…………………… (1)
To find \[p\left( -x \right)\] we will put the –x in the place of x in equation (1).
So, we get
$\Rightarrow p\left( -x \right)=\left( -x \right)+3$
$\therefore p\left( -x \right)=-x+3$………………………….(2)
Now, we will find the value of $p\left( x \right)+p\left( -x \right)$ by taking the values from equation (1) and (2).
$\begin{align}
& p\left( x \right)+p\left( -x \right)=\left( x+3 \right)+\left( -x+3 \right) \\
& =x+3-x+3 \\
\end{align}$
By cancelling x and –x we will get –
$\begin{align}
& =3+3 \\
& =6 \\
\end{align}$
$\therefore p\left( x \right)+p\left( -x \right)=6$
Hence, option (D) is the correct answer.
Note: While solving this question students should be very careful as they may do mistake while finding $p\left( -x \right)$ by taking $p\left( -x \right)=-\left( x+3 \right)=-x-3$ which is wrong and this may leads to get wrong answer.
Complete step-by-step answer:
In this question it is given that, $p\left( x \right)=x+3$ .
Here, we need to find $p\left( x \right)+p\left( -x \right)$ .
To find this first we will find \[p\left( -x \right)\]
Let us take $p\left( x \right)=x+3$…………………… (1)
To find \[p\left( -x \right)\] we will put the –x in the place of x in equation (1).
So, we get
$\Rightarrow p\left( -x \right)=\left( -x \right)+3$
$\therefore p\left( -x \right)=-x+3$………………………….(2)
Now, we will find the value of $p\left( x \right)+p\left( -x \right)$ by taking the values from equation (1) and (2).
$\begin{align}
& p\left( x \right)+p\left( -x \right)=\left( x+3 \right)+\left( -x+3 \right) \\
& =x+3-x+3 \\
\end{align}$
By cancelling x and –x we will get –
$\begin{align}
& =3+3 \\
& =6 \\
\end{align}$
$\therefore p\left( x \right)+p\left( -x \right)=6$
Hence, option (D) is the correct answer.
Note: While solving this question students should be very careful as they may do mistake while finding $p\left( -x \right)$ by taking $p\left( -x \right)=-\left( x+3 \right)=-x-3$ which is wrong and this may leads to get wrong answer.
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