
If $n\left( A \right) = 1000,n\left( B \right) = 500$ and if $n\left( {A \cap B} \right) \geqslant 1$ and $n\left( {A \cup B} \right) = p$, then
A. $500 \leqslant p \leqslant 1000$
B. $1001 \leqslant p \leqslant 1498$
C. $1000 \leqslant p \leqslant 1498$
D. $999 \leqslant p \leqslant 1499$
E. $1000 \leqslant p \leqslant 1499$
Answer
551.7k+ views
Hint: With the given details we can use them in the formula $n\left( {A \cap B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cup B} \right)$and using the given condition we get that p needs to be less than or equal to 1499 and as the cardinality of union of the sets is greater than or equal to the cardinality of the sets we get that p must be greater than or equal to 1000. combing the conditions we get the required range.
Step by step solution :
We are given that $n\left( A \right) = 1000,n\left( B \right) = 500$ and $n\left( {A \cap B} \right) \geqslant 1$and $n\left( {A \cup B} \right) = p$
We know that
$ \Rightarrow n\left( {A \cap B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cup B} \right)$
Now using the given values in this we get
$
\Rightarrow n\left( {A \cap B} \right) = 1000 + 500 - p \\
\Rightarrow n\left( {A \cap B} \right) = 1500 - p \\
$
Since $n\left( {A \cap B} \right) \geqslant 1$the value of p should be less than 1500 that is
$ \Rightarrow p \leqslant 1499$……….(1)
As we have $n\left( A \right) = 1000,n\left( B \right) = 500$
Since the union of A and B consists of all the elements of A and B
It is clear that $n\left( {A \cup B} \right) \geqslant n\left( A \right)$
Hence we get
$ \Rightarrow p \geqslant 1000$………(2)
Combining (1) and (2) we get the range of p to be
$ \Rightarrow 1000 \leqslant p \leqslant 1499$
Therefore the correct answer is option E.
Note :
In English, the union of two sets A and B is the set containing elements that are either in A or in B.
An element belongs to the intersection of two sets if the element is in both set A and in set B.
In mathematics, the cardinality of a set is a measure of the "number of elements" of the set.
Step by step solution :
We are given that $n\left( A \right) = 1000,n\left( B \right) = 500$ and $n\left( {A \cap B} \right) \geqslant 1$and $n\left( {A \cup B} \right) = p$
We know that
$ \Rightarrow n\left( {A \cap B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cup B} \right)$
Now using the given values in this we get
$
\Rightarrow n\left( {A \cap B} \right) = 1000 + 500 - p \\
\Rightarrow n\left( {A \cap B} \right) = 1500 - p \\
$
Since $n\left( {A \cap B} \right) \geqslant 1$the value of p should be less than 1500 that is
$ \Rightarrow p \leqslant 1499$……….(1)
As we have $n\left( A \right) = 1000,n\left( B \right) = 500$
Since the union of A and B consists of all the elements of A and B
It is clear that $n\left( {A \cup B} \right) \geqslant n\left( A \right)$
Hence we get
$ \Rightarrow p \geqslant 1000$………(2)
Combining (1) and (2) we get the range of p to be
$ \Rightarrow 1000 \leqslant p \leqslant 1499$
Therefore the correct answer is option E.
Note :
In English, the union of two sets A and B is the set containing elements that are either in A or in B.
An element belongs to the intersection of two sets if the element is in both set A and in set B.
In mathematics, the cardinality of a set is a measure of the "number of elements" of the set.
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