If Meselson and Stahl’s experiment is continued for four generations in bacteria, the ratio of $_{ }^{ 15 }{ N }_{ }^{ 15 }{ N }$, $_{ }^{ 15 }{ N }_{ }^{ 14 }{ N }$, $_{ }^{ 14 }{ N }_{ }^{ 14 }{ N }$ containing DNA in the fourth generation would be?
(a) 1:1:0
(b) 1:4:0
(c) 0:1:3
(d) 0:1:7
Answer
633.9k+ views
Hint: The semi-conservative nature of DNA replication was proposed by Watson and Crick but its experimental verification was done by Meselson and Stahl in Escherichia coli using a heavy isotope of nitrogen $_{ }^{ 15 }{ { N } }$ and a centrifuge.
Complete Answer:
Watson and Crick explained that the parental DNA strand would act as a template for the formation of a new strand, thus each new DNA strand would have a parental strand along with a newly synthesized strand. This phenomenon was termed as the semi- conservative nature of DNA replication (as half parental DNA was conserved).
Meselson and Stahl’s experiment proving this nature is as follows:
- E.coli was grown in a $_{ }^{ 15 }{ { NH }_{ 4 } }{ Cl }$ medium thus allowing $_{ }^{ 15 }{ { N } }$ to be incorporated into the DNA strand of this bacteria.
- Now, this bacteria was transferred to a plate containing normal $_{ }^{ 14 }{ { NH }_{ 4 } }{ Cl }$ where it was allowed to grow.
- Centrifugation after each generation of E.coli showed the presence of $_{ }^{ 15 }{ N }_{ }^{ 14 }{ N }$ hybrid DNA which indicated that the $_{ }^{ 15 }{ { N } }$ strand of DNA came from the parental strand.
- By the time we reach the fourth generation, there will be no parental $_{ }^{ 15 }{ N }_{ }^{ 15 }{ N }$ DNA strands left as they were utilized in making the hybrid strands.
- There will be 2 strands having $_{ }^{ 15 }{ N }_{ }^{ 14 }{ N }$ i.e. hybrids and 14 strands having $_{ }^{ 14 }{ N }_{ }^{ 14 }{ N }$ i.e. pure strands.
So, the correct option is ‘0:1:7’.
Note:
- Similar experiments were performed by Taylor in faba beans using radioactive thymine in 1958.
- The centrifuge used had a CsCl density gradient.
- The time required for E.coli to produce a new generation is 20 minutes.
Complete Answer:
Watson and Crick explained that the parental DNA strand would act as a template for the formation of a new strand, thus each new DNA strand would have a parental strand along with a newly synthesized strand. This phenomenon was termed as the semi- conservative nature of DNA replication (as half parental DNA was conserved).
Meselson and Stahl’s experiment proving this nature is as follows:
- E.coli was grown in a $_{ }^{ 15 }{ { NH }_{ 4 } }{ Cl }$ medium thus allowing $_{ }^{ 15 }{ { N } }$ to be incorporated into the DNA strand of this bacteria.
- Now, this bacteria was transferred to a plate containing normal $_{ }^{ 14 }{ { NH }_{ 4 } }{ Cl }$ where it was allowed to grow.
- Centrifugation after each generation of E.coli showed the presence of $_{ }^{ 15 }{ N }_{ }^{ 14 }{ N }$ hybrid DNA which indicated that the $_{ }^{ 15 }{ { N } }$ strand of DNA came from the parental strand.
- By the time we reach the fourth generation, there will be no parental $_{ }^{ 15 }{ N }_{ }^{ 15 }{ N }$ DNA strands left as they were utilized in making the hybrid strands.
- There will be 2 strands having $_{ }^{ 15 }{ N }_{ }^{ 14 }{ N }$ i.e. hybrids and 14 strands having $_{ }^{ 14 }{ N }_{ }^{ 14 }{ N }$ i.e. pure strands.
So, the correct option is ‘0:1:7’.
Note:
- Similar experiments were performed by Taylor in faba beans using radioactive thymine in 1958.
- The centrifuge used had a CsCl density gradient.
- The time required for E.coli to produce a new generation is 20 minutes.
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