If ${\log _{30}}3 = c$ and ${\log _{30}}5 = d$, then the value of ${\log _{30}}8$ is
$\left( a \right)$ 2(1 – c – d)
$\left( b \right)$3(1 + c + d)
$\left( c \right)$ 3(1 + c – d)
$\left( d \right)$ 3(1 – c – d)
Answer
626.7k+ views
Hint: In this particular type of question use the concept of logarithmic properties such that ${\log _a}{b^2} = 2{\log _a}b$, ${\log _b}\left( {\dfrac{m}{n}} \right) = {\log _b}m - {\log _b}n$, ${\log _b}b = 1$ and $\log \left( {mn} \right) = \log m + \log n$ so use these concepts to reach the solution of the given equation.
Complete step-by-step answer:
Given data,
${\log _{30}}3 = c$........................ (1)
And
${\log _{30}}5 = d$........................ (2)
Now we have to find the value of ${\log _{30}}8$
This equation is also written as, ${\log _{30}}{2^3}$
Now as we all know that according to logarithmic property the value of ${\log _a}{b^2} = 2{\log _a}b$ so use this property in the above equation we have,
So the given equation becomes,
$ \Rightarrow {\log _{30}}{2^3} = 3{\log _{30}}2$
Now 2 can be written as (30/15) so we have,
$ \Rightarrow {\log _{30}}{2^3} = 3{\log _{30}}\left( {\dfrac{{30}}{{15}}} \right)$
Now again according to logarithmic property the value of ${\log _b}\left( {\dfrac{m}{n}} \right) = {\log _b}m - {\log _b}n$ so use this property in the above equation we have,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {{{\log }_{30}}30 - {{\log }_{30}}15} \right)\]
Now the above equation is also written as,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {{{\log }_{30}}30 - {{\log }_{30}}\left( {3 \times 5} \right)} \right)\]
Now again according to logarithmic property the value of ${\log _b}b = 1$ and $\log \left( {mn} \right) = \log m + \log n$ so use these properties in the above equation we have,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {1 - \left( {{{\log }_{30}}3 + {{\log }_{30}}5} \right)} \right)\]
Now from equation (1) and (2) we have,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {1 - \left( {c + d} \right)} \right)\]
\[ \Rightarrow {\log _{30}}8 = 3\left( {1 - c - d} \right)\]
So this is the required answer.
Hence option (D) is the correct answer.
Note – Whenever we face such types of questions the key concept we have to remember is that always recall all the basic properties of log which is all stated above then simplify the given equation we want to solve according to these properties as above we will get the required answer.
Complete step-by-step answer:
Given data,
${\log _{30}}3 = c$........................ (1)
And
${\log _{30}}5 = d$........................ (2)
Now we have to find the value of ${\log _{30}}8$
This equation is also written as, ${\log _{30}}{2^3}$
Now as we all know that according to logarithmic property the value of ${\log _a}{b^2} = 2{\log _a}b$ so use this property in the above equation we have,
So the given equation becomes,
$ \Rightarrow {\log _{30}}{2^3} = 3{\log _{30}}2$
Now 2 can be written as (30/15) so we have,
$ \Rightarrow {\log _{30}}{2^3} = 3{\log _{30}}\left( {\dfrac{{30}}{{15}}} \right)$
Now again according to logarithmic property the value of ${\log _b}\left( {\dfrac{m}{n}} \right) = {\log _b}m - {\log _b}n$ so use this property in the above equation we have,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {{{\log }_{30}}30 - {{\log }_{30}}15} \right)\]
Now the above equation is also written as,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {{{\log }_{30}}30 - {{\log }_{30}}\left( {3 \times 5} \right)} \right)\]
Now again according to logarithmic property the value of ${\log _b}b = 1$ and $\log \left( {mn} \right) = \log m + \log n$ so use these properties in the above equation we have,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {1 - \left( {{{\log }_{30}}3 + {{\log }_{30}}5} \right)} \right)\]
Now from equation (1) and (2) we have,
\[ \Rightarrow {\log _{30}}{2^3} = 3\left( {1 - \left( {c + d} \right)} \right)\]
\[ \Rightarrow {\log _{30}}8 = 3\left( {1 - c - d} \right)\]
So this is the required answer.
Hence option (D) is the correct answer.
Note – Whenever we face such types of questions the key concept we have to remember is that always recall all the basic properties of log which is all stated above then simplify the given equation we want to solve according to these properties as above we will get the required answer.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
What is the full form of NDA a National Democratic class 10 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

Bharatiya Janata Party was founded in the year A 1979 class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

