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It is given in the question that,

1. Leah is 6 years older than Sue.

2. John is 5 years older than Leah.

3. The total of their ages is 41

Now, we have to formulate equations based on the above written statements. So, let us suppose that the age of Sue is $x$ years.

Then as it is given that Leah is 6 years older than Sue, so

Leah’s age = $x+6$ years

Also, it is given that John is 5 years older than Leah, so

John’s age = $(x+6)+5=x+11$ years

Now, finally the sum of their ages is equal to 41, so

$\therefore $ Sue’s age + Leah’s age + John’s age = 41

$\Rightarrow x+(x+6)+(x+11)=41$

Simplifying the above equation, we get

$\Rightarrow 3x+17=41$

Rearranging the above equation, we get

$\Rightarrow 3x=41-17=24$

Dividing both sides by 3, we get

$\Rightarrow x=\dfrac{24}{3}=8$

Here, the value of $x$ is 8.