
If l, b, h of a cuboid increased, decreased and increased by 1%, 3%, 2% respectively then the volume of the cuboid
A) Increases
B) Decreases
C) Increases or decreases depending on the original dimensions
D) Can’t be calculated with given data
Answer
584.1k+ views
Hint: Let us consider the length, breadth and height of a cuboid is \[l,b,h\] respectively.
Then the volume of the cuboid can be found using the following formula, it is clear that the product of the length, breadth and height is the volume.
Used formula: volume of the cuboid is \[V = lbh\]
Complete step by step answer:
Let us consider, the length, breadth and height of a cuboid is \[l,b,h\]respectively.
So, its volume will be \[V = lbh\]
Again,
The length, breadth and height are increased, decreased and increased by \[1\% ,3\% ,2\% \] respectively.
So, there will be change in the volume.
The length \[l\] is increased by \[1\% .\] so, the new length will be \[\dfrac{{101}}{{100}}l\]
The breadth \[b\] is decreased by \[3\% .\] so, the new breadth will be \[\dfrac{{97}}{{100}}b\]
The height \[h\] is increased by \[2\% .\] so, the new height will be \[\dfrac{{102}}{{100}}h\]
So, the volume will be
\[{V_1} = \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\]
To find the change in the volume we will find the difference between these volumes.
So,
\[V - {V_1} = lbh - \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\]
We shall solve the above equation to find the increase or decrease in volume, we get,
\[V - {V_1} = \dfrac{{1000000lbh - 999294lbh}}{{1000000}}\]
On subtracting the terms in the equation, we get,
\[V - {V_1} = \dfrac{{704lbh}}{{1000000}}\]
It gives that, \[V > {V_1}\]
Hence, the volume will be decreased when the length, breadth and height will be increased, decreased and increased by \[1\% ,3\% ,2\% \] respectively.
The correct option is (B), The resultant volume of the cuboid Decreases.
Note:
The volume of a three-dimensional shape Cuboid, in general, is equal to the amount of space occupied by the shape cuboid. The term “solid Rectangle” is also known as a cuboid. Because all the faces of a cuboid are rectangular. In a rectangular cuboid, all the angles are at right angles and the opposite faces of a cuboid are equal.
Here we use subtraction to find the increase or decrease in volume another method of substitution can also be used. The method of substitution follows,
We have \[V = lbh\] and\[{V_1} = \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\],
From \[{V_1} = \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\] we find that \[lbh = \dfrac{{100}}{{101}} \times \dfrac{{100}}{{97}} \times \dfrac{{100}}{{102}}{V_1}\]
Let us substitute l, b, h in V we get,
\[V = \dfrac{{100}}{{101}} \times \dfrac{{100}}{{97}} \times \dfrac{{100}}{{102}}{V_1}\]
That is we can conclude that V is greater than \[{V_1}\], which in turn imply that \[{V_1}\] decreases with the given decrease and increases in length, breadth and height.
Then the volume of the cuboid can be found using the following formula, it is clear that the product of the length, breadth and height is the volume.
Used formula: volume of the cuboid is \[V = lbh\]
Complete step by step answer:
Let us consider, the length, breadth and height of a cuboid is \[l,b,h\]respectively.
So, its volume will be \[V = lbh\]
Again,
The length, breadth and height are increased, decreased and increased by \[1\% ,3\% ,2\% \] respectively.
So, there will be change in the volume.
The length \[l\] is increased by \[1\% .\] so, the new length will be \[\dfrac{{101}}{{100}}l\]
The breadth \[b\] is decreased by \[3\% .\] so, the new breadth will be \[\dfrac{{97}}{{100}}b\]
The height \[h\] is increased by \[2\% .\] so, the new height will be \[\dfrac{{102}}{{100}}h\]
So, the volume will be
\[{V_1} = \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\]
To find the change in the volume we will find the difference between these volumes.
So,
\[V - {V_1} = lbh - \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\]
We shall solve the above equation to find the increase or decrease in volume, we get,
\[V - {V_1} = \dfrac{{1000000lbh - 999294lbh}}{{1000000}}\]
On subtracting the terms in the equation, we get,
\[V - {V_1} = \dfrac{{704lbh}}{{1000000}}\]
It gives that, \[V > {V_1}\]
Hence, the volume will be decreased when the length, breadth and height will be increased, decreased and increased by \[1\% ,3\% ,2\% \] respectively.
The correct option is (B), The resultant volume of the cuboid Decreases.
Note:
The volume of a three-dimensional shape Cuboid, in general, is equal to the amount of space occupied by the shape cuboid. The term “solid Rectangle” is also known as a cuboid. Because all the faces of a cuboid are rectangular. In a rectangular cuboid, all the angles are at right angles and the opposite faces of a cuboid are equal.
Here we use subtraction to find the increase or decrease in volume another method of substitution can also be used. The method of substitution follows,
We have \[V = lbh\] and\[{V_1} = \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\],
From \[{V_1} = \dfrac{{101}}{{100}} \times \dfrac{{97}}{{100}} \times \dfrac{{102}}{{100}}lbh\] we find that \[lbh = \dfrac{{100}}{{101}} \times \dfrac{{100}}{{97}} \times \dfrac{{100}}{{102}}{V_1}\]
Let us substitute l, b, h in V we get,
\[V = \dfrac{{100}}{{101}} \times \dfrac{{100}}{{97}} \times \dfrac{{100}}{{102}}{V_1}\]
That is we can conclude that V is greater than \[{V_1}\], which in turn imply that \[{V_1}\] decreases with the given decrease and increases in length, breadth and height.
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