
If each side of a triangle is double, then find the ratio of area of the new triangle thus formed and the given triangle.
A. 4:1
B. 1:4
C. 2:1
D. 1:2
Answer
518.1k+ views
Hint- In this question, first we consider a triangle with its three sides are a, b and c respectively. And find its semi-perimeter and with the help of Heron’s formula, we will calculate its area. And then after each side of a triangle is double i.e. sides of a new triangle will be 2a,2b,2c. and also we will calculate the area of the new triangle with new sides and take its ratio.
Complete step-by-step answer:
Semi perimeter of the triangle (s) = $\dfrac{{{\text{a + b + c}}}}{{\text{2}}}$
Area of triangle (A) = $\sqrt {{\text{s}}\left( {{\text{s - a}}} \right)\left( {{\text{s - b}}} \right)\left( {{\text{s - c}}} \right)} $ ………. (Heron’s formula)
As given in question,
If each sides of a triangle is double i.e.
Sides of the new triangle will be 2a,2b,2c.
Semi perimeter of the new triangle = $\dfrac{{{\text{2a + 2b + 2c}}}}{{\text{2}}}$ = $\dfrac{{{\text{a + b + c}}}}{1}$
= 2s
Now, the area of the new triangle is calculated.
Area of the new triangle = $\sqrt {{\text{2s}}\left( {{\text{2s - 2a}}} \right)\left( {{\text{2s - 2b}}} \right)\left( {{\text{2s - 2c}}} \right)} $
= $\sqrt {{{\text{2}}^{\text{4}}}{\text{s}}\left( {{\text{s - a}}} \right)\left( {{\text{s - b}}} \right)\left( {{\text{s - c}}} \right)} $
= ${2^2}$$\sqrt {{\text{s}}\left( {{\text{s - a}}} \right)\left( {{\text{s - b}}} \right)\left( {{\text{s - c}}} \right)} $
= 4 A
= 4 x area of the original triangle.
Hence, the ratio of area of the new triangle thus formed and the given triangle is 4:1.
So, option (A) is the correct answer.
Note-If base and height of a triangle are given in the question, then in this case we need to use formula for Area of a triangle is-
Area of a triangle = $\dfrac{1}{2}$ × Base × Height
Complete step-by-step answer:
Semi perimeter of the triangle (s) = $\dfrac{{{\text{a + b + c}}}}{{\text{2}}}$
Area of triangle (A) = $\sqrt {{\text{s}}\left( {{\text{s - a}}} \right)\left( {{\text{s - b}}} \right)\left( {{\text{s - c}}} \right)} $ ………. (Heron’s formula)


As given in question,
If each sides of a triangle is double i.e.
Sides of the new triangle will be 2a,2b,2c.
Semi perimeter of the new triangle = $\dfrac{{{\text{2a + 2b + 2c}}}}{{\text{2}}}$ = $\dfrac{{{\text{a + b + c}}}}{1}$
= 2s
Now, the area of the new triangle is calculated.
Area of the new triangle = $\sqrt {{\text{2s}}\left( {{\text{2s - 2a}}} \right)\left( {{\text{2s - 2b}}} \right)\left( {{\text{2s - 2c}}} \right)} $
= $\sqrt {{{\text{2}}^{\text{4}}}{\text{s}}\left( {{\text{s - a}}} \right)\left( {{\text{s - b}}} \right)\left( {{\text{s - c}}} \right)} $
= ${2^2}$$\sqrt {{\text{s}}\left( {{\text{s - a}}} \right)\left( {{\text{s - b}}} \right)\left( {{\text{s - c}}} \right)} $
= 4 A
= 4 x area of the original triangle.
Hence, the ratio of area of the new triangle thus formed and the given triangle is 4:1.
So, option (A) is the correct answer.
Note-If base and height of a triangle are given in the question, then in this case we need to use formula for Area of a triangle is-
Area of a triangle = $\dfrac{1}{2}$ × Base × Height
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Trending doubts
A number is chosen from 1 to 20 Find the probabili-class-10-maths-CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What are the public facilities provided by the government? Also explain each facility

Difference between mass and weight class 10 physics CBSE
