If \[\dfrac{{10 - 3x}}{{5 + 2x}} = \dfrac{m}{n}\]; make x as the subject of the formula. Hence, find the value of x, if 3m - 4n = 2 and n = 2.5.
(a). \[x = \dfrac{{5(2n - m)}}{{2m + 3n}}\] and \[x = \dfrac{{10}}{{31}}\]
(b). \[x = \dfrac{{2(2n - m)}}{{7m + 9n}}\] and \[x = \dfrac{1}{{21}}\]
(a). \[x = \dfrac{{7(n - m)}}{{2m + n}}\] and \[x = \dfrac{{11}}{{14}}\]
(a). \[x = \dfrac{{12(n - m)}}{{2m + 3n}}\] and \[x = \dfrac{{12}}{{31}}\]
Answer
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Hint: Solve the given equation to find x in terms of m and n. Then, solve for m and n from the given equations and find them. Then, substitute these values of m and n in the given equation to solve and find x.
Complete step-by-step answer:
Let us represent x in terms of m and n, starting from the given equation.
\[\dfrac{{10 - 3x}}{{5 + 2x}} = \dfrac{m}{n}\]
Cross-multiplying, we get:
\[n(10 - 3x) = m(5 + 2x)\]
Multiplying m and n inside the bracket, we get:
\[10n - 3nx = 5m + 2mx\]
Gather all terms containing x on the left-hand side of the equation to get as follows:
\[ - 2mx - 3nx = 5m - 10n\]
Now, take x as a common term from the left-hand side of the equations:
\[x( - 2m - 3n) = 5m - 10n\]
Solve for x to get as follows:
\[x = \dfrac{{5m - 10n}}{{ - 2m - 3n}}\]
Now take 5 as common term from the numerator to get:
\[x = \dfrac{{5(m - 2n)}}{{ - 2m - 3n}}\]
Now multiply numerator and denominator by -1 to get the final expression.
\[x = \dfrac{{5(2n - m)}}{{2m + 3n}}..........(1)\]
Given that, n = 2.5, substitute it in the equation 3m – 4n =2 to find the value of m.
\[n = 2.5..........(2)\]
\[3m - 4(2.5) = 2\]
\[3m - 10 = 2\]
Take 10 to the other side and add it with 2 to get 12.
\[3m = 2 + 10\]
\[3m = 12\]
Solve for m as follows:
\[m = \dfrac{{12}}{3}\]
Simplifying to obtain the value of m.
\[m = 4...........(3)\]
Substitute equation (3) and equation (2) in equation (1) to get as follows:
\[x = \dfrac{{5(2(2.5) - 4)}}{{2(4) + 3(2.5)}}\]
\[x = \dfrac{{5(5 - 4)}}{{8 + 7.5}}\]
\[x = \dfrac{5}{{15.5}}\]
Multiply numerator and denominator by 2 to obtain the final expression.
\[x = \dfrac{5}{{15.5}} \times \dfrac{2}{2}\]
\[x = \dfrac{{10}}{{31}}\]
Hence, the correct answer is option (a).
Note: Even though the ratio of m and n is represented as a function of x, we can solve them to find the value of x in terms of m and n. Don’t confuse yourself with the phrase “make the subject of the equation”, it just means express x explicitly.
Complete step-by-step answer:
Let us represent x in terms of m and n, starting from the given equation.
\[\dfrac{{10 - 3x}}{{5 + 2x}} = \dfrac{m}{n}\]
Cross-multiplying, we get:
\[n(10 - 3x) = m(5 + 2x)\]
Multiplying m and n inside the bracket, we get:
\[10n - 3nx = 5m + 2mx\]
Gather all terms containing x on the left-hand side of the equation to get as follows:
\[ - 2mx - 3nx = 5m - 10n\]
Now, take x as a common term from the left-hand side of the equations:
\[x( - 2m - 3n) = 5m - 10n\]
Solve for x to get as follows:
\[x = \dfrac{{5m - 10n}}{{ - 2m - 3n}}\]
Now take 5 as common term from the numerator to get:
\[x = \dfrac{{5(m - 2n)}}{{ - 2m - 3n}}\]
Now multiply numerator and denominator by -1 to get the final expression.
\[x = \dfrac{{5(2n - m)}}{{2m + 3n}}..........(1)\]
Given that, n = 2.5, substitute it in the equation 3m – 4n =2 to find the value of m.
\[n = 2.5..........(2)\]
\[3m - 4(2.5) = 2\]
\[3m - 10 = 2\]
Take 10 to the other side and add it with 2 to get 12.
\[3m = 2 + 10\]
\[3m = 12\]
Solve for m as follows:
\[m = \dfrac{{12}}{3}\]
Simplifying to obtain the value of m.
\[m = 4...........(3)\]
Substitute equation (3) and equation (2) in equation (1) to get as follows:
\[x = \dfrac{{5(2(2.5) - 4)}}{{2(4) + 3(2.5)}}\]
\[x = \dfrac{{5(5 - 4)}}{{8 + 7.5}}\]
\[x = \dfrac{5}{{15.5}}\]
Multiply numerator and denominator by 2 to obtain the final expression.
\[x = \dfrac{5}{{15.5}} \times \dfrac{2}{2}\]
\[x = \dfrac{{10}}{{31}}\]
Hence, the correct answer is option (a).
Note: Even though the ratio of m and n is represented as a function of x, we can solve them to find the value of x in terms of m and n. Don’t confuse yourself with the phrase “make the subject of the equation”, it just means express x explicitly.
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