
If $A=\left\{ a\text{, b, c, d, e, f} \right\}$ , $B=\left\{ \text{c, e, g, h} \right\}$ and $C=\left\{ a\text{, e, m, n} \right\}$, find:
(iv) $B\cap C$
(v) $C\cap A$
(vi) $A\cap B$
Answer
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Hint: To find the intersection of two given sets$A$ and set$B$ that is $A\cap B$ we find all elements which are in set $A$ as well as in set $B$.That is we have to find the common elements.
Complete step-by-step answer:
Now, as given in the question,
$A=\left\{ a\text{, b, c, d, e, f} \right\}$
$B=\left\{ \text{c, e, g, h} \right\}$
$C=\left\{ a\text{, e, m, n} \right\}$
So, (iv) $B\cap C$
(vi) For finding $B\cap C$ we have to find elements in set $B$ which are also in set $C$ that are common to both sets.
Now, elements in set $B=\left\{ \text{c, e, g, h} \right\}$ and elements in set $C=\left\{ \text{a, e, m, n} \right\}$
So, common elements in set $B$ and set $C$ are : $c,e$
So, we can say $B\cap C=\left\{ e \right\}$
Therefore, $B\cap C=\left\{ e \right\}$
(v) $C\cap A$
For finding $C\cap A$, we follow the same process as in part (iv) that is we find elements which are common in both the set $A$ and set $C$ .
Now, elements in set $C=\left\{ \text{a, e, m, n} \right\}$ and elements in set $A=\left\{ \text{a, b, c, d, e, f} \right\}$ .
So, common elements in set $A$ and set $C$ are : $a,e$
So, we can say $C\cap A=\left\{ a,e \right\}$
Therefore, $C\cap A=\left\{ a,e \right\}$
(vi) $A\cap B$
Again, in this case we have to find $A\cap B$.For this we follow the procedure as earlier in part (v). We have to find all elements in set $A$ which are also in set $B$ , that is common elements in both set $A$ and set $B$.
Now , elements in set $A=\left\{ a\text{, b, c, d, e, f} \right\}$and elements in set $B=\left\{ \text{c, e, g, h} \right\}$ .
So, common elements in set$A$ and set$B$ are : $c,e$
So, we can say $A\cap B=\left\{ c,e \right\}$
Therefore, $A\cap B=\left\{ c,e \right\}$
Note: In all the examples above, the intersection is a subset of each set forming the intersection that is $A\cap B\subseteq A$ and$A\cap B\subseteq B$ . Two sets whose intersection is an empty set then they are called disjoint sets.
Complete step-by-step answer:
Now, as given in the question,
$A=\left\{ a\text{, b, c, d, e, f} \right\}$
$B=\left\{ \text{c, e, g, h} \right\}$
$C=\left\{ a\text{, e, m, n} \right\}$
So, (iv) $B\cap C$
(vi) For finding $B\cap C$ we have to find elements in set $B$ which are also in set $C$ that are common to both sets.
Now, elements in set $B=\left\{ \text{c, e, g, h} \right\}$ and elements in set $C=\left\{ \text{a, e, m, n} \right\}$
So, common elements in set $B$ and set $C$ are : $c,e$
So, we can say $B\cap C=\left\{ e \right\}$
Therefore, $B\cap C=\left\{ e \right\}$
(v) $C\cap A$
For finding $C\cap A$, we follow the same process as in part (iv) that is we find elements which are common in both the set $A$ and set $C$ .
Now, elements in set $C=\left\{ \text{a, e, m, n} \right\}$ and elements in set $A=\left\{ \text{a, b, c, d, e, f} \right\}$ .
So, common elements in set $A$ and set $C$ are : $a,e$
So, we can say $C\cap A=\left\{ a,e \right\}$
Therefore, $C\cap A=\left\{ a,e \right\}$
(vi) $A\cap B$
Again, in this case we have to find $A\cap B$.For this we follow the procedure as earlier in part (v). We have to find all elements in set $A$ which are also in set $B$ , that is common elements in both set $A$ and set $B$.
Now , elements in set $A=\left\{ a\text{, b, c, d, e, f} \right\}$and elements in set $B=\left\{ \text{c, e, g, h} \right\}$ .
So, common elements in set$A$ and set$B$ are : $c,e$
So, we can say $A\cap B=\left\{ c,e \right\}$
Therefore, $A\cap B=\left\{ c,e \right\}$
Note: In all the examples above, the intersection is a subset of each set forming the intersection that is $A\cap B\subseteq A$ and$A\cap B\subseteq B$ . Two sets whose intersection is an empty set then they are called disjoint sets.
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