
If action and reaction were to act on the same body, then
$A.$ Resultant would be $0$
$B.$ Body would not move at all
$C.$ Both $(A)$ and $(B)$
$D.$ None of these
Answer
574.2k+ views
Hint: We have to use the concept of Newton’s third law of motion. This law states that for every action there is an equal and opposite reaction. Action and Reaction never balance each other. Action and reaction can never be unequal.
Complete step by step solution:
We know that Sir Isaac Newton gave three laws of motion among which we are going to analyse the third law of motion. Newton’s third law of motion can be stated as follows:-
‘’To every action there is equal and opposite reaction.’’
Action and reaction are nothing but equal and opposite forces which act on different bodies and do not balance each other. But when we apply this for the same body then they do balance each other and resultant would be $0$and the body would not move.
Hence, option $(C)$ is correct.
Additional Information:
Important points of newton’s third laws of motion are as follows:-
$(i)$ Forces always occur in pair one is called action and the other is called reaction.
$(ii)$ Action and reaction are equal in magnitude but opposite in direction.
$(iii)$ Action and reaction always act on different bodies.
$(iv)$ Action and reaction both occur at the same time and not one after another. There is no time lag between them.
$(v)$ We can consider any of the two forces as action then the other is reaction.
$(vi)$ We suppose that two bodies $1$ and $2$ are interacting. Let $\overrightarrow{{{F}_{1}}}$ be the force due to $1$ acts on $2$ and $\overrightarrow{{{F}_{2}}}$ be the force due to $2$ acts on $1$ then mathematically newton’s third law can be stated as follows:-
$\overrightarrow{{{F}_{1}}}=-\overrightarrow{{{F}_{2}}}$.
Note:
We should take care of the fact that both action and reaction always act on different bodies not on the same body. We have considered different bodies only because it is the demand of the problem. We should also take care that both the forces act simultaneously at the same time.
Complete step by step solution:
We know that Sir Isaac Newton gave three laws of motion among which we are going to analyse the third law of motion. Newton’s third law of motion can be stated as follows:-
‘’To every action there is equal and opposite reaction.’’
Action and reaction are nothing but equal and opposite forces which act on different bodies and do not balance each other. But when we apply this for the same body then they do balance each other and resultant would be $0$and the body would not move.
Hence, option $(C)$ is correct.
Additional Information:
Important points of newton’s third laws of motion are as follows:-
$(i)$ Forces always occur in pair one is called action and the other is called reaction.
$(ii)$ Action and reaction are equal in magnitude but opposite in direction.
$(iii)$ Action and reaction always act on different bodies.
$(iv)$ Action and reaction both occur at the same time and not one after another. There is no time lag between them.
$(v)$ We can consider any of the two forces as action then the other is reaction.
$(vi)$ We suppose that two bodies $1$ and $2$ are interacting. Let $\overrightarrow{{{F}_{1}}}$ be the force due to $1$ acts on $2$ and $\overrightarrow{{{F}_{2}}}$ be the force due to $2$ acts on $1$ then mathematically newton’s third law can be stated as follows:-
$\overrightarrow{{{F}_{1}}}=-\overrightarrow{{{F}_{2}}}$.
Note:
We should take care of the fact that both action and reaction always act on different bodies not on the same body. We have considered different bodies only because it is the demand of the problem. We should also take care that both the forces act simultaneously at the same time.
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