
If a,b,c are distinct prime integers such that ${{a}^{2}}{{b}^{3}}{{c}^{4}}=49392$, find the values of $a,b$ and $c$ .
Answer
531.3k+ views
Hint: Here in this question we have been asked to find the values of $a,b$ and $c$ which are distinct prime integers such that ${{a}^{2}}{{b}^{3}}{{c}^{4}}=49392$. For that we will prime factorize the given number 49392.
Complete step by step answer:
Now considering from the question we have been asked to find the values of $a,b$ and $c$ which are distinct prime integers such that ${{a}^{2}}{{b}^{3}}{{c}^{4}}=49392$.
For that we will prime factorize the given number 49392.
The prime factorization of 49392 can be done as follows:
Firstly we will use 2 the first prime number to factorize the given number 49392. By doing that we will have
$\begin{align}
& 2\left| \!{\underline {\,
49392 \,}} \right. \\
& 2\left| \!{\underline {\,
24696 \,}} \right. \\
& 2\left| \!{\underline {\,
12348 \,}} \right. \\
& 2\left| \!{\underline {\,
6174 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
3087 \,}} \right. \\
\end{align}$
As 3087 can’t be factorized using 2 we will use the next prime number 3. By doing this we will have
$\begin{align}
& 2\left| \!{\underline {\,
49392 \,}} \right. \\
& 2\left| \!{\underline {\,
24696 \,}} \right. \\
& 2\left| \!{\underline {\,
12348 \,}} \right. \\
& 2\left| \!{\underline {\,
6174 \,}} \right. \\
& 3\left| \!{\underline {\,
3087 \,}} \right. \\
& 3\left| \!{\underline {\,
1029 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
343 \,}} \right. \\
\end{align}$
As 343 can’t be factorized using 3 we will use the prime number 7 as 5 can’t be used. By doing this we will have
$\begin{align}
& 2\left| \!{\underline {\,
49392 \,}} \right. \\
& 2\left| \!{\underline {\,
24696 \,}} \right. \\
& 2\left| \!{\underline {\,
12348 \,}} \right. \\
& 2\left| \!{\underline {\,
6174 \,}} \right. \\
& 3\left| \!{\underline {\,
3087 \,}} \right. \\
& 3\left| \!{\underline {\,
1029 \,}} \right. \\
& 7\left| \!{\underline {\,
343 \,}} \right. \\
& 7\left| \!{\underline {\,
49 \,}} \right. \\
& 7\left| \!{\underline {\,
7 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
1 \,}} \right. \\
\end{align}$
Hence 49392 can be expressed as ${{2}^{4}}{{3}^{2}}{{7}^{3}}$ .
Hence we can conclude that the values of $a,b$ and $c$ which are distinct prime integers such that ${{a}^{2}}{{b}^{3}}{{c}^{4}}=49392$ are $3,7,2$ respectively.
Note: While answering questions of this type we should be sure with our calculations that we are going to perform in between the steps. Someone can unintentionally make a mistake and can consider the prime factorization result as ${{2}^{4}}{{3}^{3}}{{7}^{2}}$ which will lead us to end up having the conclusion as $a=7,b=3,c=2$ which is a wrong answer.
Complete step by step answer:
Now considering from the question we have been asked to find the values of $a,b$ and $c$ which are distinct prime integers such that ${{a}^{2}}{{b}^{3}}{{c}^{4}}=49392$.
For that we will prime factorize the given number 49392.
The prime factorization of 49392 can be done as follows:
Firstly we will use 2 the first prime number to factorize the given number 49392. By doing that we will have
$\begin{align}
& 2\left| \!{\underline {\,
49392 \,}} \right. \\
& 2\left| \!{\underline {\,
24696 \,}} \right. \\
& 2\left| \!{\underline {\,
12348 \,}} \right. \\
& 2\left| \!{\underline {\,
6174 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
3087 \,}} \right. \\
\end{align}$
As 3087 can’t be factorized using 2 we will use the next prime number 3. By doing this we will have
$\begin{align}
& 2\left| \!{\underline {\,
49392 \,}} \right. \\
& 2\left| \!{\underline {\,
24696 \,}} \right. \\
& 2\left| \!{\underline {\,
12348 \,}} \right. \\
& 2\left| \!{\underline {\,
6174 \,}} \right. \\
& 3\left| \!{\underline {\,
3087 \,}} \right. \\
& 3\left| \!{\underline {\,
1029 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
343 \,}} \right. \\
\end{align}$
As 343 can’t be factorized using 3 we will use the prime number 7 as 5 can’t be used. By doing this we will have
$\begin{align}
& 2\left| \!{\underline {\,
49392 \,}} \right. \\
& 2\left| \!{\underline {\,
24696 \,}} \right. \\
& 2\left| \!{\underline {\,
12348 \,}} \right. \\
& 2\left| \!{\underline {\,
6174 \,}} \right. \\
& 3\left| \!{\underline {\,
3087 \,}} \right. \\
& 3\left| \!{\underline {\,
1029 \,}} \right. \\
& 7\left| \!{\underline {\,
343 \,}} \right. \\
& 7\left| \!{\underline {\,
49 \,}} \right. \\
& 7\left| \!{\underline {\,
7 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
1 \,}} \right. \\
\end{align}$
Hence 49392 can be expressed as ${{2}^{4}}{{3}^{2}}{{7}^{3}}$ .
Hence we can conclude that the values of $a,b$ and $c$ which are distinct prime integers such that ${{a}^{2}}{{b}^{3}}{{c}^{4}}=49392$ are $3,7,2$ respectively.
Note: While answering questions of this type we should be sure with our calculations that we are going to perform in between the steps. Someone can unintentionally make a mistake and can consider the prime factorization result as ${{2}^{4}}{{3}^{3}}{{7}^{2}}$ which will lead us to end up having the conclusion as $a=7,b=3,c=2$ which is a wrong answer.
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