
If a thermometer reads the freezing point of water as 20 degrees Celsius and boiling point as 150 degrees. Celsius, how much kilometers read when the actual temperature is 60 degree Celsius.
A). 98 degree Celsius
B). 110 degree Celsius
C). 150 degree Celsius
D). 60 degree Celsius
Answer
525.3k+ views
Hint: Here’s the expression. With the help of scale we calculate the temperature
$\dfrac{{t - freezing{\text{ temp}}}}{{boiling{\text{ temp - freezing temp}}}} = \dfrac{{actual\; temperature}}{{100}}$
Complete step by step solution:
Given,
Freezing temperature is equal to 20 degree Celsius
Boiling temperature is equal to 150 degree Celsius
Actual temperature is equal to 60 degree Celsius
We, measure it by a scale
Here’s the expression to solving the new reading of the thermometer
$\dfrac{c}{{100}} = \dfrac{{t - {t_f}}}{{{t_b} - {t_f}}}$ --- (A)
Here’s
C is the actual temperature,
t is the reading of new thermometer,
$t_b$ is the boiling temperature,
$t_f$ is the freezing temperature
we know the values of
actual temperature that is 60 degree Celsius,
boiling temperature that is 20 degree Celsius,
freezing temperature that is 150 degree Celsius
Put the value in equation(A)
$\dfrac{{60}}{{100}} = \dfrac{{t - 20}}{{150 - 20}}$
Now, we solve for the reading of new thermometer
$
\dfrac{{60}}{{100}} = \dfrac{{t - 20}}{{150 - 20}} \\
\Rightarrow \dfrac{6}{{10}} = \dfrac{{t - 20}}{{130}} \\
$
Now, we do cross multiply
$
130 \times 6 = 10(t - 20) \\
\Rightarrow 780 = 10t - 200 \\
$
Now, separate them one side be variable and other side be the numeric term
$
780 + 200 = 10t \\
\Rightarrow 980 = 10t \\
\Rightarrow t = \dfrac{{980}}{{10}} \\
\Rightarrow t = {98^0} \\
$
Here, we get the value of the reading of the new thermometer with the help of boiling point, freezing point and actual temperature.
Now, the temperature is 98 degree Celsius
So, the option (A) is correct.
Note: The thermometer is the instrument for measuring the temperature of a system. In the thermodynamics there is an important role of the thermometer to calculate the change in temperature. In simple terms, if we have to calculate the change in temperature then we have to subtract the old temperature from the new one.
$\dfrac{{t - freezing{\text{ temp}}}}{{boiling{\text{ temp - freezing temp}}}} = \dfrac{{actual\; temperature}}{{100}}$
Complete step by step solution:
Given,
Freezing temperature is equal to 20 degree Celsius
Boiling temperature is equal to 150 degree Celsius
Actual temperature is equal to 60 degree Celsius
We, measure it by a scale
Here’s the expression to solving the new reading of the thermometer
$\dfrac{c}{{100}} = \dfrac{{t - {t_f}}}{{{t_b} - {t_f}}}$ --- (A)
Here’s
C is the actual temperature,
t is the reading of new thermometer,
$t_b$ is the boiling temperature,
$t_f$ is the freezing temperature
we know the values of
actual temperature that is 60 degree Celsius,
boiling temperature that is 20 degree Celsius,
freezing temperature that is 150 degree Celsius
Put the value in equation(A)
$\dfrac{{60}}{{100}} = \dfrac{{t - 20}}{{150 - 20}}$
Now, we solve for the reading of new thermometer
$
\dfrac{{60}}{{100}} = \dfrac{{t - 20}}{{150 - 20}} \\
\Rightarrow \dfrac{6}{{10}} = \dfrac{{t - 20}}{{130}} \\
$
Now, we do cross multiply
$
130 \times 6 = 10(t - 20) \\
\Rightarrow 780 = 10t - 200 \\
$
Now, separate them one side be variable and other side be the numeric term
$
780 + 200 = 10t \\
\Rightarrow 980 = 10t \\
\Rightarrow t = \dfrac{{980}}{{10}} \\
\Rightarrow t = {98^0} \\
$
Here, we get the value of the reading of the new thermometer with the help of boiling point, freezing point and actual temperature.
Now, the temperature is 98 degree Celsius
So, the option (A) is correct.
Note: The thermometer is the instrument for measuring the temperature of a system. In the thermodynamics there is an important role of the thermometer to calculate the change in temperature. In simple terms, if we have to calculate the change in temperature then we have to subtract the old temperature from the new one.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

