
If a matrix has 5 elements, what are the possible orders it can have?
Answer
486.6k+ views
Hint: This question is based on the chapter matrices and determinants. It involves basic concepts like the formation of a matrix using certain rows and columns and also the number of elements it contains.
Complete step-by-step answer:
Now, let us start the question with the assumption of having a certain number of rows and columns.
Let the number of rows be m, and the number of columns is n.
Where m and n are both integers.
Now, the condition given in the question is
\[ \Rightarrow m \times n = 5\]
Let us start assigning some values to the number of rows and find the corresponding column.
If the number of columns comes out to be a positive integer, then the matrix assumed can exist; otherwise, it cannot.
Now, let us start with m = 1; thus, we get,
\[ \Rightarrow 1 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 5\]
As is a positive integer, therefore, the matrix exists.
Now, let us start with m = 2; thus, we get,
\[ \Rightarrow 2 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 2.5\]
As it is not a positive integer, therefore, the matrix does not exist.
Now, let us start with m = 3; thus, we get,
\[ \Rightarrow 3 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 1.67\]
As it is not a positive integer, therefore, the matrix does not exist.
Now, let us start with m = 4; thus, we get,
\[ \Rightarrow 4 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 1.25\]
As it is not a positive integer, therefore, the matrix does not exist.
Now, let us start with m = 5; thus, we get,
\[ \Rightarrow 5 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 1\]
As is a positive integer, therefore, the matrix exists.
Thus, the possible number of the matrix is two.
So, the correct answer is “2”.
Note: This is a question directly from matrices and determinants. One should be well versed with its concepts to solve this question. Do not commit calculation mistakes, and be sure of the final answer.
Complete step-by-step answer:
Now, let us start the question with the assumption of having a certain number of rows and columns.
Let the number of rows be m, and the number of columns is n.
Where m and n are both integers.
Now, the condition given in the question is
\[ \Rightarrow m \times n = 5\]
Let us start assigning some values to the number of rows and find the corresponding column.
If the number of columns comes out to be a positive integer, then the matrix assumed can exist; otherwise, it cannot.
Now, let us start with m = 1; thus, we get,
\[ \Rightarrow 1 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 5\]
As is a positive integer, therefore, the matrix exists.
Now, let us start with m = 2; thus, we get,
\[ \Rightarrow 2 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 2.5\]
As it is not a positive integer, therefore, the matrix does not exist.
Now, let us start with m = 3; thus, we get,
\[ \Rightarrow 3 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 1.67\]
As it is not a positive integer, therefore, the matrix does not exist.
Now, let us start with m = 4; thus, we get,
\[ \Rightarrow 4 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 1.25\]
As it is not a positive integer, therefore, the matrix does not exist.
Now, let us start with m = 5; thus, we get,
\[ \Rightarrow 5 \times n = 5\]
After solving for n, we get its value as shown below,
\[ \Rightarrow n = 1\]
As is a positive integer, therefore, the matrix exists.
Thus, the possible number of the matrix is two.
So, the correct answer is “2”.
Note: This is a question directly from matrices and determinants. One should be well versed with its concepts to solve this question. Do not commit calculation mistakes, and be sure of the final answer.
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