
If a copper – containing compound contains \[4.999%\]\[Cu\]by mass and there are \[2\]copper atoms per formula unit, what is the molar mass of the compound?
A) \[2547g/mol\]
B) \[47.50g/mol\]
C) \[31.75g/mol\]
D) \[1274g/mol\]
Answer
501k+ views
Hint : In order to solve this question first determine the number of atoms per formula unit. Then we would multiply the atomic weight of elements with its atomic number.
Complete step-by-step solution:
let us assume the molar mass of compound \[=\]\[M\]
According to the question there are two Copper atoms in \[1mole\]of atom i.e. \[128gms\] of atom,
Here, copper mass is given \[4.999%\]
Now, we will calculate the molar mass of the compound-
\[\begin{align}
& \Rightarrow \left( \dfrac{4.999}{100} \right)\times M=128gms \\
& \Rightarrow M=\dfrac{12800}{4.99}=2547g/mol \\
\end{align}\]
So, the right option is a) \[2547g/mol\].
Note: Italian physicist Amedeo Avogadro found the concept of molar mass. Molar mass is mainly used to convert a mass to an amount of substance that is expressed as atoms, molecules, and the ions.
\[%\]of copper) \[\times \]Molar mass \[=\]Mass of copper
Complete step-by-step solution:
let us assume the molar mass of compound \[=\]\[M\]
According to the question there are two Copper atoms in \[1mole\]of atom i.e. \[128gms\] of atom,
Here, copper mass is given \[4.999%\]
Now, we will calculate the molar mass of the compound-
\[\begin{align}
& \Rightarrow \left( \dfrac{4.999}{100} \right)\times M=128gms \\
& \Rightarrow M=\dfrac{12800}{4.99}=2547g/mol \\
\end{align}\]
So, the right option is a) \[2547g/mol\].
Note: Italian physicist Amedeo Avogadro found the concept of molar mass. Molar mass is mainly used to convert a mass to an amount of substance that is expressed as atoms, molecules, and the ions.
\[%\]of copper) \[\times \]Molar mass \[=\]Mass of copper
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

