If a : b = c : d and e : f = g : h, prove that ae + bf : ae – bf = cg + dh : cg –dh
Answer
Verified
Hint: Here we have to multiply both the equations by dividendo and componendo. As per this rule, if $\dfrac{a}{b} = \dfrac{c}{d}$, Then this can be expressed as $\dfrac{{a + b}}{{a - b}} = \dfrac{{c + d}}{{c - d}}$
Multiplying both the equation (1) and (2) $\dfrac{{ae}}{{bf}} = \dfrac{{cg}}{{dh}}$ By dividendo and componendo $\dfrac{{ae + bf}}{{ae - bf}} = \dfrac{{cg + dh}}{{cg - dh}}$
NOTE: Whenever you come to this type of problem first convert the given form to a rational form that multiplies both the equation and after applying the dividendo and componendo get the final answer.
×
Sorry!, This page is not available for now to bookmark.