
If ‘A’ and ‘B’ two events such that P (C) $={\dfrac{1}{4}}.$ P (B) $=\dfrac{1}{8},$ the find P (not A and not B)
Answer
579.9k+ views
Hint: Remember the formula P $\left( \text{A}\,\text{or}\ \text{B} \right)=\text{P}\left( \text{A} \right)+\text{P}\left( \text{B} \right)-\,\text{P}\,\left( \text{A}\cap \,\text{B} \right)$ for P (not A and not B) subtract P(A and B) from 1 because we know that the sum of probability of a work to happen and not happen is always 1.
Complete step by step solution:
Given, that these are 2 events A and P also
Probability of A = P (A)
P (A) = $\dfrac{1}{4}$ (given)
Probability of B = P (B)
P(B) = $\text{P}\dfrac{1}{2}$ (given)
Also
$\text{P}\,\left( \text{A}\,\cap \,\text{B} \right)\dfrac{1}{8}$
We have to find P (not A and not B)
$\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$ = we have to find . Now,
There is a formula for $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$ not is can also be rotten like $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$
\[\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\,\cap \,\text{B }\!\!'\!\!\text{ } \right)\,=\,\text{P}\,\left( \text{A}\cup \text{B} \right)\]
If we solve now, we get
P (not A not B) = $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$
= $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$
$\text{1-P}\,\left( \text{A}\,\text{or}\,\text{B} \right)$
\[[Therefore, \,\text{P}\,\left( \text{A}\,\text{or}\,\text{B} \right)\,=\,\text{P}(\text{A})+\text{P}(\text{B})-P(\text{A}\cap \text{B})]\,=\,1-[\text{P}\,(\text{A})+\text{P}(\text{B})-\text{P}(\text{A}\cap \text{B})]\]
= $1-\left( {\dfrac{1}{4}}+\ \dfrac{1}{2}-\ \dfrac{1}{8} \right)$
$=1-\left( \dfrac{2}{8}+\dfrac{4}{8}-\dfrac{1}{8} \right)$
$=1-\dfrac{5}{8}$
$=\dfrac{3}{8}$
The value for P (not A not B) $=\dfrac{3}{8}$
Note: In this type of question first remember the formula and then try to find the suitable formula according to the given information from the question and also we need to know the representation of everything like in this question
P(not A not B) = P (A’∩B’) = P ( A ∪B’)
This is also equally important.
Complete step by step solution:
Given, that these are 2 events A and P also
Probability of A = P (A)
P (A) = $\dfrac{1}{4}$ (given)
Probability of B = P (B)
P(B) = $\text{P}\dfrac{1}{2}$ (given)
Also
$\text{P}\,\left( \text{A}\,\cap \,\text{B} \right)\dfrac{1}{8}$
We have to find P (not A and not B)
$\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$ = we have to find . Now,
There is a formula for $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$ not is can also be rotten like $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$
\[\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\,\cap \,\text{B }\!\!'\!\!\text{ } \right)\,=\,\text{P}\,\left( \text{A}\cup \text{B} \right)\]
If we solve now, we get
P (not A not B) = $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$
= $\text{P}\,\left( \text{A }\!\!'\!\!\text{ }\cap \,\text{B }\!\!'\!\!\text{ } \right)$
$\text{1-P}\,\left( \text{A}\,\text{or}\,\text{B} \right)$
\[[Therefore, \,\text{P}\,\left( \text{A}\,\text{or}\,\text{B} \right)\,=\,\text{P}(\text{A})+\text{P}(\text{B})-P(\text{A}\cap \text{B})]\,=\,1-[\text{P}\,(\text{A})+\text{P}(\text{B})-\text{P}(\text{A}\cap \text{B})]\]
= $1-\left( {\dfrac{1}{4}}+\ \dfrac{1}{2}-\ \dfrac{1}{8} \right)$
$=1-\left( \dfrac{2}{8}+\dfrac{4}{8}-\dfrac{1}{8} \right)$
$=1-\dfrac{5}{8}$
$=\dfrac{3}{8}$
The value for P (not A not B) $=\dfrac{3}{8}$
Note: In this type of question first remember the formula and then try to find the suitable formula according to the given information from the question and also we need to know the representation of everything like in this question
P(not A not B) = P (A’∩B’) = P ( A ∪B’)
This is also equally important.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

