If A + C = B, then tan A tan B tan C =
A) tan A + tan B + tan C
B) tan B – tan C – tan A
C) tan A + tan B – tan C
D) – (tan A + tan B + tan C)
Answer
636.3k+ views
Hint: In this problem we will use the trigonometric formula of tan (A+B). Then we will use the given condition (A + C = B) to get the solution.
Complete step-by-step answer:
Now, it is given that A + C = B, so we will use this condition to find the solution of the given problem.
Now, $\tan {\text{ (A + B) = }}\dfrac{{{\text{tan A + }}{\text{ tan B}}}}{{1{\text{ }} - {\text{ tan A tan B}}}}$
Now in the above property we will put the values, A = A and B = C.so, we get
$\tan {\text{ (A + C) = }}\dfrac{{{\text{tan A + }}{\text{ tan C}}}}{{1{\text{ }} - {\text{ tan A tan C}}}}$ As, A + C = B, so the above equation can be written as
$\tan {\text{ B = }}\dfrac{{{\text{tan A + }}{\text{ tan C}}}}{{1{\text{ }} - {\text{ tan A tan C}}}}$
Now cross- multiplying both sides, we get
$\tan {\text{ B(1 - tan A tan C) = tan A + tan C}}$
$\tan {\text{ B - tan A tan B tan C = tan A + tan C}}$
${\text{tan A tan B tan C = tan B - tan A - tan C}}$
Which can be written as ${\text{tan A tan B tan C = tan B - tan C - tan A}}$.
So, option (B) is the correct answer.
Note: Such problems look difficult but they are very easy to solve. You just have to apply a property and use the condition given in the question. By applying the condition in the property, you will get the correct answer by doing a simple calculation. Just make sure that you use proper identity and do all the calculations correctly.
Complete step-by-step answer:
Now, it is given that A + C = B, so we will use this condition to find the solution of the given problem.
Now, $\tan {\text{ (A + B) = }}\dfrac{{{\text{tan A + }}{\text{ tan B}}}}{{1{\text{ }} - {\text{ tan A tan B}}}}$
Now in the above property we will put the values, A = A and B = C.so, we get
$\tan {\text{ (A + C) = }}\dfrac{{{\text{tan A + }}{\text{ tan C}}}}{{1{\text{ }} - {\text{ tan A tan C}}}}$ As, A + C = B, so the above equation can be written as
$\tan {\text{ B = }}\dfrac{{{\text{tan A + }}{\text{ tan C}}}}{{1{\text{ }} - {\text{ tan A tan C}}}}$
Now cross- multiplying both sides, we get
$\tan {\text{ B(1 - tan A tan C) = tan A + tan C}}$
$\tan {\text{ B - tan A tan B tan C = tan A + tan C}}$
${\text{tan A tan B tan C = tan B - tan A - tan C}}$
Which can be written as ${\text{tan A tan B tan C = tan B - tan C - tan A}}$.
So, option (B) is the correct answer.
Note: Such problems look difficult but they are very easy to solve. You just have to apply a property and use the condition given in the question. By applying the condition in the property, you will get the correct answer by doing a simple calculation. Just make sure that you use proper identity and do all the calculations correctly.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

