# If \[98x=2\]. Then find the value of x.

Last updated date: 26th Mar 2023

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Answer

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Hint: Take LHS = 98x and RHS = 2. Take 2 to LHS, it becomes an algebraic expression. Simplify the expression received and solve the entity to obtain the value of x.

Complete step-by-step answer:

An algebraic expression is an expression built up from integers, constants, variables and exponentiation by an exponentiation by an exponent that is a rational number.

Given is the expression,

\[98x=2\]

Taking 2 to the LHS, we get

\[98x-2=0\]

Taking 2 common on LHS,

\[2\left( 49x-1 \right)=0\]

\[\therefore \] We get \[49x-1=0\]

\[\begin{align}

& \therefore 49x=1 \\

& x=\dfrac{1}{49} \\

\end{align}\]

Hence, we got the value of x as \[\dfrac{1}{49}\].

Note:

The expression can be solved directly.

Take 98 to the denominator of RHS. 98 is a multiple of 2. So 98 has a common factor. So 98 can be written as \[2\times 49\], which is equal to 98.

\[\begin{align}

& \therefore 98x=2 \\

& \Rightarrow x=\dfrac{2}{98}=\dfrac{2}{2\times 49} \\

\end{align}\]

Cancel out 2 on the numerator and denominator.

\[\therefore x=\dfrac{1}{49}\].

Complete step-by-step answer:

An algebraic expression is an expression built up from integers, constants, variables and exponentiation by an exponentiation by an exponent that is a rational number.

Given is the expression,

\[98x=2\]

Taking 2 to the LHS, we get

\[98x-2=0\]

Taking 2 common on LHS,

\[2\left( 49x-1 \right)=0\]

\[\therefore \] We get \[49x-1=0\]

\[\begin{align}

& \therefore 49x=1 \\

& x=\dfrac{1}{49} \\

\end{align}\]

Hence, we got the value of x as \[\dfrac{1}{49}\].

Note:

The expression can be solved directly.

Take 98 to the denominator of RHS. 98 is a multiple of 2. So 98 has a common factor. So 98 can be written as \[2\times 49\], which is equal to 98.

\[\begin{align}

& \therefore 98x=2 \\

& \Rightarrow x=\dfrac{2}{98}=\dfrac{2}{2\times 49} \\

\end{align}\]

Cancel out 2 on the numerator and denominator.

\[\therefore x=\dfrac{1}{49}\].

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