Hint: Take LHS = 98x and RHS = 2. Take 2 to LHS, it becomes an algebraic expression. Simplify the expression received and solve the entity to obtain the value of x.
Complete step-by-step answer: An algebraic expression is an expression built up from integers, constants, variables and exponentiation by an exponentiation by an exponent that is a rational number. Given is the expression, \[98x=2\] Taking 2 to the LHS, we get \[98x-2=0\] Taking 2 common on LHS, \[2\left( 49x-1 \right)=0\] \[\therefore \] We get \[49x-1=0\] \[\begin{align} & \therefore 49x=1 \\ & x=\dfrac{1}{49} \\ \end{align}\] Hence, we got the value of x as \[\dfrac{1}{49}\].
Note: The expression can be solved directly. Take 98 to the denominator of RHS. 98 is a multiple of 2. So 98 has a common factor. So 98 can be written as \[2\times 49\], which is equal to 98. \[\begin{align} & \therefore 98x=2 \\ & \Rightarrow x=\dfrac{2}{98}=\dfrac{2}{2\times 49} \\ \end{align}\] Cancel out 2 on the numerator and denominator. \[\therefore x=\dfrac{1}{49}\].
×
Sorry!, This page is not available for now to bookmark.