
If $3x - 2y = 13$ and $xy = 15$, then find the value of $27{x^3} - 8{y^3}$.
Answer
569.7k+ views
Hint: We are required to find the value of the given equation provided the conditions of the variables involved. So, we will use the algebraic identity $(a - b)^3$ to solve the question and get the required value.
Complete step-by-step answer:
We need to find the value of the given equation: $27{x^3} - 8{y^3}$
We are given that $3x - 2y = 13$and $xy = 15$
On cubing both sides of the equation $3x - 2y = 13$, we get
${\left( {3x - 2y} \right)^3} = \left( {{{13}^3}} \right)$ …eq (1)
Using the algebraic identity ${\left( {a - b} \right)^3} = {a^3} - {b^3} - 3ab\left( {a - b} \right)$ , we get
$ \Rightarrow {\left( {3x - 2y} \right)^3} = {\left( {3x} \right)^3} - {\left( {2y} \right)^3} - 3\left( {3x} \right)\left( {2y} \right)\left( {3x - 2y} \right)$
Now, we can substitute the above value in eq (1). On substituting the value, we get
$ \Rightarrow $${\left( {3x} \right)^3} - {\left( {2y} \right)^3} - 3\left( {3x} \right)\left( {2y} \right)\left( {3x - 2y} \right) = {\left( {13} \right)^3}$
$ \Rightarrow 27{x^3} - 8{y^3} - 18xy\left( {3x - 2y} \right) = 2197$
We were given, initially, the values of: $3x - 2y = 13$, $xy = 15$. Substituting these values in the above equation, we get:
$ \Rightarrow 27{x^3} - 8{y^3} - 18\left( 5 \right)\left( {13} \right) = 2197$
$ \Rightarrow 27{x^3} - 8{y^3} - 1170 = 2197$
$ \Rightarrow 27{x^3} - 8{y^3} = 3367$
Hence, the value of the required equation $27{x^3} - 8{y^3}$ is 3367.
Note: In such problems, we generally take a look at the given initial conditions and solve accordingly. We can also use various properties as there can be many ways to solve a question. We can also solve this question using the identity $a^3$ – $b^3$ in the equation $27{x^3} - 8{y^3}$ and then upon expanding we will get our desired answer. By substitution also, we can find the value of $27{x^3} - 8{y^3}$.
We used an algebraic identity in the above mentioned question. We can define the algebraic identities as: an equality which holds for each and every value of its variables is called an algebraic identity or an identity is an equality relating one mathematical expression with the other.
In other words, we can say that an algebraic identity is basically an equality in which every value of its variables holds true.
Complete step-by-step answer:
We need to find the value of the given equation: $27{x^3} - 8{y^3}$
We are given that $3x - 2y = 13$and $xy = 15$
On cubing both sides of the equation $3x - 2y = 13$, we get
${\left( {3x - 2y} \right)^3} = \left( {{{13}^3}} \right)$ …eq (1)
Using the algebraic identity ${\left( {a - b} \right)^3} = {a^3} - {b^3} - 3ab\left( {a - b} \right)$ , we get
$ \Rightarrow {\left( {3x - 2y} \right)^3} = {\left( {3x} \right)^3} - {\left( {2y} \right)^3} - 3\left( {3x} \right)\left( {2y} \right)\left( {3x - 2y} \right)$
Now, we can substitute the above value in eq (1). On substituting the value, we get
$ \Rightarrow $${\left( {3x} \right)^3} - {\left( {2y} \right)^3} - 3\left( {3x} \right)\left( {2y} \right)\left( {3x - 2y} \right) = {\left( {13} \right)^3}$
$ \Rightarrow 27{x^3} - 8{y^3} - 18xy\left( {3x - 2y} \right) = 2197$
We were given, initially, the values of: $3x - 2y = 13$, $xy = 15$. Substituting these values in the above equation, we get:
$ \Rightarrow 27{x^3} - 8{y^3} - 18\left( 5 \right)\left( {13} \right) = 2197$
$ \Rightarrow 27{x^3} - 8{y^3} - 1170 = 2197$
$ \Rightarrow 27{x^3} - 8{y^3} = 3367$
Hence, the value of the required equation $27{x^3} - 8{y^3}$ is 3367.
Note: In such problems, we generally take a look at the given initial conditions and solve accordingly. We can also use various properties as there can be many ways to solve a question. We can also solve this question using the identity $a^3$ – $b^3$ in the equation $27{x^3} - 8{y^3}$ and then upon expanding we will get our desired answer. By substitution also, we can find the value of $27{x^3} - 8{y^3}$.
We used an algebraic identity in the above mentioned question. We can define the algebraic identities as: an equality which holds for each and every value of its variables is called an algebraic identity or an identity is an equality relating one mathematical expression with the other.
In other words, we can say that an algebraic identity is basically an equality in which every value of its variables holds true.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

