# If 200g of 25% sulphuric acid solution was added to 300g of 40% sulphuric acid solution. Find the concentration of acid in the mixture.

Last updated date: 27th Mar 2023

•

Total views: 306.6k

•

Views today: 7.83k

Answer

Verified

306.6k+ views

Hint: In order to solve this question find the total amount of acid. This will give us a clear picture of what our approach should be then simply find the concentration by doing simple mathematics.

Complete step-by-step answer:

We have given that,

200g of 25% sulphuric acid solution was added to 300g of 40% sulphuric acid solution.

And we have to find the concentration of acid in the mixture.

Now,

Amount of acid in the first solution = 25% of 200g

= $\dfrac{{25}}{{100}} \times 200$

= $50$g

Also in the same way,

Amount of acid in the second solution = 40% of 300g

=$ \dfrac{{40}}{{100}} \times 300$

=$ 120$g

Now,

The total amount of acid $ = 50 + 120$

=$ 170$g

Now, we have to calculate the required concentration

The required concentration =$\dfrac{{170}}{{\left( {200 + 300} \right)}} \times 100$

=$ 34\% $

Thus the concentration of acid in the mixture is 34%.

Note: Whenever we face such types of questions the key concept is that we should write what is given to us then, convert the statements into equations, like we did in this question. Here, we write what is given to us then we simply convert the statements into equations and then we find the total amount of acid. Thus we get our desired answer.

Complete step-by-step answer:

We have given that,

200g of 25% sulphuric acid solution was added to 300g of 40% sulphuric acid solution.

And we have to find the concentration of acid in the mixture.

Now,

Amount of acid in the first solution = 25% of 200g

= $\dfrac{{25}}{{100}} \times 200$

= $50$g

Also in the same way,

Amount of acid in the second solution = 40% of 300g

=$ \dfrac{{40}}{{100}} \times 300$

=$ 120$g

Now,

The total amount of acid $ = 50 + 120$

=$ 170$g

Now, we have to calculate the required concentration

The required concentration =$\dfrac{{170}}{{\left( {200 + 300} \right)}} \times 100$

=$ 34\% $

Thus the concentration of acid in the mixture is 34%.

Note: Whenever we face such types of questions the key concept is that we should write what is given to us then, convert the statements into equations, like we did in this question. Here, we write what is given to us then we simply convert the statements into equations and then we find the total amount of acid. Thus we get our desired answer.

Recently Updated Pages

If abc are pthqth and rth terms of a GP then left fraccb class 11 maths JEE_Main

If the pthqth and rth term of a GP are abc respectively class 11 maths JEE_Main

If abcdare any four consecutive coefficients of any class 11 maths JEE_Main

If A1A2 are the two AMs between two numbers a and b class 11 maths JEE_Main

If pthqthrth and sth terms of an AP be in GP then p class 11 maths JEE_Main

One root of the equation cos x x + frac12 0 lies in class 11 maths JEE_Main

Trending doubts

What was the capital of Kanishka A Mathura B Purushapura class 7 social studies CBSE

Difference Between Plant Cell and Animal Cell

Write an application to the principal requesting five class 10 english CBSE

Ray optics is valid when characteristic dimensions class 12 physics CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Tropic of Cancer passes through how many states? Name them.

Write the 6 fundamental rights of India and explain in detail

Write a letter to the principal requesting him to grant class 10 english CBSE

Name the Largest and the Smallest Cell in the Human Body ?