
Identify the reducing agent in the following reactions.
A.$4N{H_3} + 5{O_2} \to 4NO + 6{H_2}O$
B.${H_2}O + {F_2} \to HF + HOF$
C.$F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}$
D.$2{H_2} + {O_2} \to 2{H_2}O$
Answer
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Hint: We have to know that, the reducing agent (likewise called a reducer, or electron benefactor) is a component or compound that loses or gives an electron to an electron beneficiary (called the oxidizing specialist, oxidant, or oxidizer) in a redox synthetic response. The reducer's oxidation state increments while the oxidizer's declines; this is communicated by saying that reducers go through oxidation.
Complete answer:
We have to know that, to explain, in a redox response, the specialist that loses or indicates electrons, that is oxidized, and that diminishes, is known as the reducer or decreasing specialist, while the specialist that takes or gets electrons, that is diminished, and that oxidizes, is known as the oxidizer or oxidizing specialist. A lessening specialist is subsequently oxidized by an oxidizer when it loses electrons that are acquired by this oxidizing specialist, which itself is all the while decreased by the reducer.
For $4N{H_3} + 5{O_2} \to 4NO + 6{H_2}O$ ,
Lessening specialist is the one, which diminishes other substances (by evacuation of oxygen or expansion of hydrogen) and itself gets oxidized.
In the above response, ammonia is the decreasing specialist as it is being oxidized by oxygen structure nitric oxide and water.
Therefore, the reducing agent is ammonia.
For ${H_2}O + {F_2} \to HF + HOF$ ,
In the above reaction, the reducing agent is water.
For $F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}$ ,
In the above reaction, the reducing agent is carbon monoxide.
For $2{H_2} + {O_2} \to 2{H_2}O$ ,
In the above reaction, the reducing agent is hydrogen.
Note:
Reducing agents and oxidizing specialists are the ones liable for consumption, which is the corruption of metals because of electrochemical movement. Consumption requires an anode and cathode to occur. The anode is a component that loses electrons, accordingly oxidation consistently happens in the anode, and the cathode is a component that acquires electrons, subsequently decreasing consistently happens in the cathode.
Complete answer:
We have to know that, to explain, in a redox response, the specialist that loses or indicates electrons, that is oxidized, and that diminishes, is known as the reducer or decreasing specialist, while the specialist that takes or gets electrons, that is diminished, and that oxidizes, is known as the oxidizer or oxidizing specialist. A lessening specialist is subsequently oxidized by an oxidizer when it loses electrons that are acquired by this oxidizing specialist, which itself is all the while decreased by the reducer.
For $4N{H_3} + 5{O_2} \to 4NO + 6{H_2}O$ ,
Lessening specialist is the one, which diminishes other substances (by evacuation of oxygen or expansion of hydrogen) and itself gets oxidized.
In the above response, ammonia is the decreasing specialist as it is being oxidized by oxygen structure nitric oxide and water.
Therefore, the reducing agent is ammonia.
For ${H_2}O + {F_2} \to HF + HOF$ ,
In the above reaction, the reducing agent is water.
For $F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}$ ,
In the above reaction, the reducing agent is carbon monoxide.
For $2{H_2} + {O_2} \to 2{H_2}O$ ,
In the above reaction, the reducing agent is hydrogen.
Note:
Reducing agents and oxidizing specialists are the ones liable for consumption, which is the corruption of metals because of electrochemical movement. Consumption requires an anode and cathode to occur. The anode is a component that loses electrons, accordingly oxidation consistently happens in the anode, and the cathode is a component that acquires electrons, subsequently decreasing consistently happens in the cathode.
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