
Identify the incorrect statement:
A. The \[S-S-S\] bond angles in \[{{S}_{8}}\] and \[{{S}_{6}}\] rings are the same
B. Rhombic and monoclinic sulphur have \[{{S}_{8}}\] molecules
C. \[{{S}_{2}}\] is paramagnetic like oxygen
D. \[{{S}_{8}}\] rings has a crown shape
Answer
579.6k+ views
Hint: Sulphur has puckered \[{{S}_{8}}\] rings with crown conformation, sulphur is also known as Engel's sulphur contain \[{{S}_{6}}\] rings arranged in a chair conformation.
Complete step by step answer:
->Option 1st: The \[S-S-S\] bond points in the s8 and \[{{S}_{6}}\] the ring are the equivalent. This announcement isn't right since the state of \[{{S}_{8}}\] is like a crown while the state of \[{{S}_{6}}\] is hexagonal.
->Option 2nd: Rhombic and monoclinic sulfur have \[{{S}_{8}}\] particles: this announcement is likewise right.
->Option 3rd: \[{{S}_{2}}\] paramagnetic like oxygen: we know, Oxygen is paramagnetic in nature in view of oxygen having two unpaired electrons in the valence shell. Likewise sulfur has a place with an oxygen family that is the reason sulfur, \[{{S}_{2}}\] is also paramagnetic subsequently, it is right.
->Option 4th: \[{{S}_{8}}\] ring has crown shape, no doubt it is additionally right proclamation. \[{{S}_{8}}\] has crown shape.
The $S-S-S$ bond angles in the \[{{S}_{8}}\] and \[{{S}_{6}}\] rings are the same. The $S_6$ molecule has a chair-form hexagon ring with the same bond length as that in \[{{S}_{8}}\] but with somewhat smaller bond angles i.e. bond lengths are same but bond angles are different.
Hence, the correct option is A. The \[S-S-S\] bond angles in \[{{S}_{8}}\] and \[{{S}_{6}}\] rings are the same
Note:
The \[{{S}_{8}}\] molecule has a zigzag shape (“crown”), which allows for \[S-S-S\] angles of about \[{{107}^{\circ }}\] quite close to the optimum and \[{{S}_{6}}\], which indeed does exist, isn’t planar but has a “chair” configuration similar to cyclohexane.
Complete step by step answer:
->Option 1st: The \[S-S-S\] bond points in the s8 and \[{{S}_{6}}\] the ring are the equivalent. This announcement isn't right since the state of \[{{S}_{8}}\] is like a crown while the state of \[{{S}_{6}}\] is hexagonal.
->Option 2nd: Rhombic and monoclinic sulfur have \[{{S}_{8}}\] particles: this announcement is likewise right.
->Option 3rd: \[{{S}_{2}}\] paramagnetic like oxygen: we know, Oxygen is paramagnetic in nature in view of oxygen having two unpaired electrons in the valence shell. Likewise sulfur has a place with an oxygen family that is the reason sulfur, \[{{S}_{2}}\] is also paramagnetic subsequently, it is right.
->Option 4th: \[{{S}_{8}}\] ring has crown shape, no doubt it is additionally right proclamation. \[{{S}_{8}}\] has crown shape.
The $S-S-S$ bond angles in the \[{{S}_{8}}\] and \[{{S}_{6}}\] rings are the same. The $S_6$ molecule has a chair-form hexagon ring with the same bond length as that in \[{{S}_{8}}\] but with somewhat smaller bond angles i.e. bond lengths are same but bond angles are different.
Hence, the correct option is A. The \[S-S-S\] bond angles in \[{{S}_{8}}\] and \[{{S}_{6}}\] rings are the same
Note:
The \[{{S}_{8}}\] molecule has a zigzag shape (“crown”), which allows for \[S-S-S\] angles of about \[{{107}^{\circ }}\] quite close to the optimum and \[{{S}_{6}}\], which indeed does exist, isn’t planar but has a “chair” configuration similar to cyclohexane.
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