Question

Identify the coordinates of the point which lies on the y-axis at a distance of 4 units in the negative direction of y axis.
A. (0,4)
B. (4,0)
C. (0,-4)
D. (-4,0)

Answer 1

Hint: This particular question is based on coordinate geometry, here we have to locate a point on the cartesian plane about which some information has been given in the question, as per the question the point lies on Y axis so it is clear that X coordinate can be taken as 0.

Complete step-by-step answer:
Before really diving into locating the point on the cartesian plane we must know some basic things about it,

There are four quadrants, if a point is located in,
Quadrant number 1- The upper right-hand corner of the graph is the first quadrant. In this quadrant the values of x and y both are positive.
Quadrant number 2- The upper left-hand corner of the graph is the second quadrant. In this quadrant, the value of x is negative whereas the value of y is positive.
Quadrant number 3- The lower left-hand corner of the graph is the third quadrant. It contains the negative values of both x and y.
Quadrant number 4- Finally, the fourth quarter is at the lower right-hand corner, that has a positive value of x and negative values of y.
According to the question our point lies on Y axis therefore this is evident that X coordinate is zero
Then it says that point lies on Y axis at a distance of 4 units in negative direction of Y axis this means that Y coordinate is negative that is -4
Therefore coordinates are (0,-4)
Plotting on the graph as

Note: This is a 2-Dimensional plane where the point exists on XY plane but if suppose the point would have existed outside the plane in space another axis would have come into picture that is Z axis which is perpendicular to the plane of XY axis.