Question

Identify the compound \[X\] on the basis of the reaction given below. Also write the name and chemical formula of \[A,B,C\] .
\[X + Zn = A + {H_2};X + HCl = B + {H_2}O;X + C{H_3}COOH = C + {H_2}O\]

Answer 1

Hint: A strong base like sodium hydroxide reacts with the metal to form a new compound along with the liberation of hydrogen gas. Sodium hydroxide on reaction with acids undergoes neutralization reactions along with the liberation of a water molecule.

Complete answer:
Chemical compounds are classified into acids, bases, and neutral compounds. Bases are compounds that consist of hydroxide ions or lone pairs of electrons and these lone pairs of electrons can be available for ready donation. Bases are classified as strong bases and weak bases.
One example of a strong base is sodium hydroxide with a molecular formula of \[NaOH\] . it consists of a hydroxide group and this compound can easily abstract a proton easily.
Sodium hydroxide reacts with Zinc metal to form a compound known as sodium zincate along with the liberation of hydrogen gas.
\[NaOH + Zn = N{a_2}Zn{O_2} + {H_2}\]
Thus, the compound A is sodium zincate with a molecular formula of \[N{a_2}Zn{O_2}\]
Sodium hydroxide on treatment with hydrochloric acid forms a salt known as sodium chloride and water. The chemical reaction is as follows:
\[NaOH + HCl = NaCl + {H_2}O\]
Thus, the compound B is sodium chloride with molecular formula \[NaCl\]
Sodium hydroxide on treatment with acetic acid forms a compound known as sodium acetate and water. The chemical reaction is as follows:
\[NaOH + C{H_3}COOH = C{H_3}COONa + {H_2}O\]
Thus, the compound C is sodium acetate with a molecular formula of \[C{H_3}COONa\]

Note:
Acid upon treatment with bases undergo neutralization reactions and forms water as one of the products which is a neutral compound. In the other product, the metal atom in the base gets substituted in the place of the hydrogen atom due to the less reactivity of hydrogen.