Question

Identify (A) and (B):
(1). $Ba{C_2} + {N_2}\xrightarrow{\vartriangle }\left( B \right)$
(2). $Ca{C_2} + {N_2}\xrightarrow{\vartriangle }\left( A \right)$
(A). $A:Ca\left( {N = C = N} \right);B:Ba{\left( {C \equiv N} \right)_2}$
(B). $A:Ca\left( {N = C = N} \right);B:B{a_2}{\left( {C \equiv N} \right)_4}$
(C). $A:Ca{\left( {N = C = N} \right)_2};B:Ba{\left( {C \equiv N} \right)_2}$
(D). $A:Ca{\left( {N = C = N} \right)_2};B:B{a_2}{\left( {C \equiv N} \right)_4}$

Answer 1

Hint: Gas solid reaction describes gas solid reaction systems, focusing on the four phenomena that are external mass transfer, pore diffusion, adsorption or desorption and chemical reactions. Solid gas reactants are present as a natural part of the environment. In an open process, neither condensing nor storing of the gas- phase reactant is necessary.

Complete step by step answer:
Calcium carbide has a chemical formula of $Ca{C_2}$. It is a solid it is produced from a mixture of line and coke at approximately $2,200^\circ c$ . It is an endothermic reaction.
Calcium carbide $\left( {Ca{C_2}} \right)$ is reacted with nitrogen $\left( {{N_2}} \right)$ at a high temperature and this reaction can be written as:
$Ca{C_2}\left( s \right) + {N_2}\left( g \right)\xrightarrow{\vartriangle }CaC{N_2}\left( s \right) + 2C\left( s \right)$
(Calcium carbide) (Nitrogen) (Calcium cyanamide) (Carbon)
This reaction is known as a gas-solid reaction. The product formed in this reaction is known as calcium cyanamide $\left( {CaC{N_2}} \right)$ . It is a relatively slow reaction and thus it is necessary to design the reactor such that the contact between the nitrogen gas and the solid calcium carbide is promoted to maximum. This reaction occurs at a high temperature. Carbon is also produced as a result of the reaction but it remains entrapped in the cyan-amide.
Now, Barium carbide has a chemical formula of $Ba{C_2}$ . It is produced by reducing the Barium oxide with carbon at high temperature. Also, barium carbonate powder can be reduced by using metallic magnesium in the presence of carbon to produce barium carbide. It reacts similarly as calcium carbide, but however it is more fusible.
Barium carbide reacts with nitrogen $\left( {{N_2}} \right)$ at a high temperature to form barium cyanide $\left( {Ba{{\left( {CN} \right)}_2}} \right)$ . This reaction can be written as
$Ba{C_2}\left( s \right) + {N_2}\left( g \right)\xrightarrow{\vartriangle }Ba{\left( {CN} \right)_2}\left( s \right)$

So, the correct answer is Option A.

Note: Calcium Cyanamide is crushed and can be sold as a fertilizer or as an agent for removing titanium from steel or it can be converted into ‘black cyanide’ whereas barium cyanide is used in metallurgy and electroplating.