Question

I have confusion: \[1debye = 10 - 18esucm = 3.335 \times {10^{ - 30}}C - m\]( coulomb meter), How is it? please prove. Thanks

Answer 1

Hint: One debye = \[{10^{ - 18}}\] esu centimeter or about \[3.336 \times {10^{ - 30}}\] coulomb meters. This worth is generally the magnitude of the electric dipole moment of numerous molecules.
Evidently Fairbrother was the first to utilize the term, yet Jenkins utilizes the unit, giving mathematical qualities as products of \[{10^{ - 18}}\] esu, and a couple of months after the fact Sugden gives mathematical values without the saying they are "in the usual units." So the debye is one of those units that was being used by professionals before it got a name

Complete step by step answer:
Debye: A unit of electric dipole moment that has endured different varying definitions symbol,\[D\] . The unit is named for P.J.W Debye
Dipole Moment (\[\mu \] ) between two charges isolated by distance d is
\[\mu = q \times d\]
Verifiably the debye was characterized as the dipole moment coming about because of two charges of opposite sign however an equivalent size of \[{10^{ - 10}}\] statcoulomb (for the most part called e.s.u. (electrostatic unit) in more established writing), which were separated by\[\;1\] angstrom
Note: \[{10^{ - 10}}\] statcoulomb is around\[0.2083\] units of rudimentary charge.
The ångström is of an order of magnitude near that of a regular covalent bond.
$1A^{\circ}$= 100pm = {10^{ - 8}}cm = {10^{ - 10}}m\].
One debye equals to \[1 \times {10^{ - 21}}C{m^2}/s\]divided by the speed of light in vacuum. Then again,\[1Cm = 2.9979 \times {10^{29}}D\]
The littlest SI unit of electric dipole moment is the yocto coulomb-meter, which is around \[300,000D\]
SI denies the use of prefixes to the two individuals from a compound unit or the compounding of prefixes, accordingly precluding such units as the femtocoulomb-femtometre or the micro yocto coulomb-meter separately