
i) A rectangular field is \[16\dfrac{1}{2}m\] long and \[12\dfrac{2}{5}m\] wide. Find the perimeter of the field.
ii) Evaluate \[88 - \{ 5 - ( - 48) + ( - 16)\} \]
Answer
569.1k+ views
Hint: Here we have two questions. First question can be solved by using the formula of the perimeter of the rectangle. Using given length and width we can find the perimeter of the field easily. Second question can be solved if you know simple addition and some knowledge about multiplications of signs.
Complete step-by-step answer:
i) We know the dimensions of rectangular field are:
Length \[l = 16\dfrac{1}{2}\;m\]
Breadth \[b = 12\dfrac{2}{5}\;m\]
Perimeter of rectangle is \[ = 2(l + b)\]
But we convert mixed fraction into improper fraction.
\[16\dfrac{1}{2} = \dfrac{{(16 \times 2) + 1}}{2} = \dfrac{{33}}{2}\] Which is length.
\[12\dfrac{2}{5} = \dfrac{{(12 \times 5) + 2}}{5} = \dfrac{{62}}{5}\] Which is breadth.
Perimeter \[ = 2(l + b)\]
Substituting length and breadth.
\[ = 2 \times \left( {\dfrac{{33}}{2} + \dfrac{{62}}{5}} \right)\]
L.C.M. of 2 and 5 is 10. Simplifying we get,
\[ = 2 \times \left( {\dfrac{{(33 \times 5) + (62 \times 2)}}{{10}}} \right)\]
\[ = 2 \times \left( {\dfrac{{165 + 124}}{{10}}} \right)\]
\[ = 2 \times \left( {\dfrac{{289}}{{10}}} \right)\] (Dividing 10 by 2)
\[ = \dfrac{{289}}{5}\;m\]
We can stop here. We can convert this improper fraction to mixed fraction.
\[ = 57\dfrac{4}{5}\;m\]
We get this result by dividing 289 by 5. We get the remainder 4. Quotient as 57.
Using \[{\text{quotient}}\dfrac{{{\text{remainder}}}}{{{\text{denominator as it is}}{\text{.}}}}\] this, substituting we get the required result.
Hence the perimeter of the field is \[57\dfrac{4}{5}\;m\] .
So, the correct answer is “ \[57\dfrac{4}{5}\;m\] ”.
II) \[88 - \{ 5 - ( - 48) + ( - 16)\} \]
First we simplify the terms in brackets. We know multiplication of negative term and negative term gives positive term and multiplication of positive term and negative term gives negative term. Using this we get:
\[ = 88 - \{ 5 + 48 - 16\} \]
\[ = 88 - \{ 37\} \]
\[ = 51\]
Thus, \[88 - \{ 5 - ( - 48) + ( - 16)\} = 51\]
So, the correct answer is “51”.
Note: In the first problem they gave the dimensions length and width in mixed fraction. Convert it into proper fractions and then solve. Also note the units of both length and width. Sometimes they can ask the perimeter in mixed fraction, that is why we converted the mixed fraction into proper fraction. Second problem all we did is dimple addition.
Complete step-by-step answer:
i) We know the dimensions of rectangular field are:
Length \[l = 16\dfrac{1}{2}\;m\]
Breadth \[b = 12\dfrac{2}{5}\;m\]
Perimeter of rectangle is \[ = 2(l + b)\]
But we convert mixed fraction into improper fraction.
\[16\dfrac{1}{2} = \dfrac{{(16 \times 2) + 1}}{2} = \dfrac{{33}}{2}\] Which is length.
\[12\dfrac{2}{5} = \dfrac{{(12 \times 5) + 2}}{5} = \dfrac{{62}}{5}\] Which is breadth.
Perimeter \[ = 2(l + b)\]
Substituting length and breadth.
\[ = 2 \times \left( {\dfrac{{33}}{2} + \dfrac{{62}}{5}} \right)\]
L.C.M. of 2 and 5 is 10. Simplifying we get,
\[ = 2 \times \left( {\dfrac{{(33 \times 5) + (62 \times 2)}}{{10}}} \right)\]
\[ = 2 \times \left( {\dfrac{{165 + 124}}{{10}}} \right)\]
\[ = 2 \times \left( {\dfrac{{289}}{{10}}} \right)\] (Dividing 10 by 2)
\[ = \dfrac{{289}}{5}\;m\]
We can stop here. We can convert this improper fraction to mixed fraction.
\[ = 57\dfrac{4}{5}\;m\]
We get this result by dividing 289 by 5. We get the remainder 4. Quotient as 57.
Using \[{\text{quotient}}\dfrac{{{\text{remainder}}}}{{{\text{denominator as it is}}{\text{.}}}}\] this, substituting we get the required result.
Hence the perimeter of the field is \[57\dfrac{4}{5}\;m\] .
So, the correct answer is “ \[57\dfrac{4}{5}\;m\] ”.
II) \[88 - \{ 5 - ( - 48) + ( - 16)\} \]
First we simplify the terms in brackets. We know multiplication of negative term and negative term gives positive term and multiplication of positive term and negative term gives negative term. Using this we get:
\[ = 88 - \{ 5 + 48 - 16\} \]
\[ = 88 - \{ 37\} \]
\[ = 51\]
Thus, \[88 - \{ 5 - ( - 48) + ( - 16)\} = 51\]
So, the correct answer is “51”.
Note: In the first problem they gave the dimensions length and width in mixed fraction. Convert it into proper fractions and then solve. Also note the units of both length and width. Sometimes they can ask the perimeter in mixed fraction, that is why we converted the mixed fraction into proper fraction. Second problem all we did is dimple addition.
Recently Updated Pages
Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Find the mode and median of the data 13 16 12 14 1-class-9-maths-CBSE

What were the main changes brought about by the Bolsheviks class 9 social science CBSE

What is the theme or message of the poem The road not class 9 english CBSE

What are the major achievements of the UNO class 9 social science CBSE

Explain the importance of pH in everyday life class 9 chemistry CBSE

Differentiate between parenchyma collenchyma and sclerenchyma class 9 biology CBSE

