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How would you balance $Na+C{{l}_{2}}\to NaCl$?

Answer
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Hint: Balancing of chemical equations generally involves the addition of stoichiometric coefficients to the reactants and products whereas reactants are those substances which present at left side of the equation and reactant are those substances which present on right side of the equation.

Complete answer:
Balancing chemical equals is important because chemical equations must follow the law of conservation of mass and the law of constant proportions. Balanced chemical equations can also be defined as those equations which have the same number of atoms of each element on the reactant side as well as the product side.
Equations can be balanced by following steps:
1. First write the unbalanced equation in which chemical formula of the substance is given in this question equation given is:
$Na+C{{l}_{2}}\to NaCl$
2. Compare the number of atoms given on both sides, there is one atom of sodium on both sides while on the reactant side there are two chlorine atoms but on product there is only one chlorine atom.
3. After that stoichiometric coefficients are added to molecules containing an element which has different number of atoms in the reactant side and product side now we can compare the difference in chloride and sodium ions on both side so the equation can be balanced in the following way:
$2Na+C{{l}_{2}}\to 2NaCl$
4. Now check again whether the number of atoms on both sides are equal or not.
Hence, the balanced equation is $2Na+C{{l}_{2}}\to 2NaCl$.

Note: Stoichiometric coefficient generally describes the total number of molecules of a chemical species which participate in a chemical reaction. It gives us information about the ratio between the reacting species and the products formed in the reaction.