
How many times can $46$ go into $300$?
Answer
525.3k+ views
Hint: The term “times” in mathematics refers to the operation of multiplication. So basically the above question is asking us the number which must be multiplied with $46$ such that we obtain the highest number which is less than or equal to $300$. For finding out the number, we need to consider the division of $300$ by $46$. Then we need to consider the whole number part of the value obtained after performing the division. That number will be the required answer to the above question.
Complete step by step solution:
According to the question, we have to find out the number of times can the number $46$ go into $300$. We know that in mathematics, the term “times” means to multiply two numbers. Therefore, we can say that the above question is asking us to find out the number which must be multiplied with $46$ such that we obtain the highest number which is less than or equal to $300$. For this, we have to consider the division of the number $300$ by the number $46$. So we divide $300$ by $46$ as shown below.
$46\overset{6.5}{\overline{\left){\begin{align}
& 300 \\
& \underline{276} \\
& 240 \\
& \underline{230} \\
& \underline{10} \\
\end{align}}\right.}}$
From the above division, we got the value $6.5$. Considering the whole number part of this value, we get the number of times to be equal to $6$.
Hence, the required number of times which $46$ can go into $300$ has been finally found to be equal to $6$.
Note: We must note that we do not have to conclude the result of the division of $300$ by $46$ as the final answer to the question. In the question, we have been asked the number of times in which $46$ can go into $300$. That number cannot be a decimal number and has to be a whole number. For this reason, we considered the whole number part of the result of division.
Complete step by step solution:
According to the question, we have to find out the number of times can the number $46$ go into $300$. We know that in mathematics, the term “times” means to multiply two numbers. Therefore, we can say that the above question is asking us to find out the number which must be multiplied with $46$ such that we obtain the highest number which is less than or equal to $300$. For this, we have to consider the division of the number $300$ by the number $46$. So we divide $300$ by $46$ as shown below.
$46\overset{6.5}{\overline{\left){\begin{align}
& 300 \\
& \underline{276} \\
& 240 \\
& \underline{230} \\
& \underline{10} \\
\end{align}}\right.}}$
From the above division, we got the value $6.5$. Considering the whole number part of this value, we get the number of times to be equal to $6$.
Hence, the required number of times which $46$ can go into $300$ has been finally found to be equal to $6$.
Note: We must note that we do not have to conclude the result of the division of $300$ by $46$ as the final answer to the question. In the question, we have been asked the number of times in which $46$ can go into $300$. That number cannot be a decimal number and has to be a whole number. For this reason, we considered the whole number part of the result of division.
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