Question

How do you solve $x-15=28$ ?

Answer 1

Hint: To solve the given linear equation i.e. $x-15=28$, we will require the value of x. For that we are going to rearrange the given equation in such a fashion so that x terms are written on the one side of the equation and the constant terms (which have no x term) on the other side of the equation. Thus, we will get the value of x.

Complete step by step answer:
The equation given in the above problem is as follows:
$x-15=28$
As you can see that the highest power of the variable (x) in the above equation is 1 so the above equation is a linear equation. And we are going to solve this linear equation by writing x terms on one side of the equation and constant terms on the other side of the equation. Adding 15 on both the sides of the above equation we get,
$\Rightarrow x-15+15=28+15$
In the L.H.S of the above equation, +15 and -15 will be cancelled out and we are left with:
$\Rightarrow x=43$
From the above, we got the value of x as 43. And as x is the solution of the above equation so the solution of the above equation is 43.

Note:
We can check the solution of the equation which we have found above by substituting that value of x in the given equation and see whether this value of x is satisfying the equation or not.
The value of x which we solved above is 43. Substituting this value of x in the given equation we get,
$\begin{align}
  & \Rightarrow 43-15=28 \\
 & \Rightarrow 28=28 \\
\end{align}$
As you can see that L.H.S = R.H.S so the value of x which we have found in the above solution is correct.