
How do you solve \[x - 7 = 13\] ?
Answer
544.8k+ views
Hint: The given equation is an algebraic equation. It is a combination of variable and the constant. Here in this question, we have to solve the given equation by shifting or by transforming the terms and we use arithmetic operations wherever it is necessary. Hence, we obtain the required solution.
Complete step-by-step answer:
The equation is an algebraic equation. The algebraic equation or expression is defined as the combination of variables and constants. The alphabets are variables and the numbers are constant. In the algebraic equation or expression, we have arithmetic operations also. Here in this question, we have equation \[x - 7 = 13\] , here x is a variable.
Now consider the equation \[x - 7 = 13\]
Now we add 7 to the equation we have
\[ \Rightarrow x - 7 + 7 = 13 + 7\]
On simplifying we have
\[ \Rightarrow x = 20\]
We can also solve the above equation by another method
Consider the given equation
\[x - 7 = 13\]
Take the -7 to the RHS we have
\[ \Rightarrow x = 13 + 7\]
On simplifying we get
\[ \Rightarrow x = 20\]
Hence we have solved the given equation and hence obtained the solution.
We can also verify the obtained answer is correct or not.
Consider the given equation
\[x - 7 = 13\]
Substitute the value of x as 20 in the above equation we have
\[ \Rightarrow 20 - 7 = 13\]
On simplifying we have
\[ \Rightarrow 13 = 13\]
Hence we have obtained the LHS is equal to the RHS.
Hence the value x = 20 is the correct one.
So, the correct answer is “ x = 20”.
Note: We must take care of the sign of the number while shifting or transforming the term either from LHS to RHS or from RHS to LHS. This is an algebraic equation which is having the degree of equation is 1 and we have obtained only one value. The arithmetic operations are used to solve these kinds of problems.
Complete step-by-step answer:
The equation is an algebraic equation. The algebraic equation or expression is defined as the combination of variables and constants. The alphabets are variables and the numbers are constant. In the algebraic equation or expression, we have arithmetic operations also. Here in this question, we have equation \[x - 7 = 13\] , here x is a variable.
Now consider the equation \[x - 7 = 13\]
Now we add 7 to the equation we have
\[ \Rightarrow x - 7 + 7 = 13 + 7\]
On simplifying we have
\[ \Rightarrow x = 20\]
We can also solve the above equation by another method
Consider the given equation
\[x - 7 = 13\]
Take the -7 to the RHS we have
\[ \Rightarrow x = 13 + 7\]
On simplifying we get
\[ \Rightarrow x = 20\]
Hence we have solved the given equation and hence obtained the solution.
We can also verify the obtained answer is correct or not.
Consider the given equation
\[x - 7 = 13\]
Substitute the value of x as 20 in the above equation we have
\[ \Rightarrow 20 - 7 = 13\]
On simplifying we have
\[ \Rightarrow 13 = 13\]
Hence we have obtained the LHS is equal to the RHS.
Hence the value x = 20 is the correct one.
So, the correct answer is “ x = 20”.
Note: We must take care of the sign of the number while shifting or transforming the term either from LHS to RHS or from RHS to LHS. This is an algebraic equation which is having the degree of equation is 1 and we have obtained only one value. The arithmetic operations are used to solve these kinds of problems.
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