
How do you solve the equation \[5{{y}^{2}}=30y\] ?
Answer
537k+ views
Hint: Take all the terms to the L.H.S. Divide both sides with 5 to simplify the equation. Now, take y common from the two terms and factorize the expression. Substitute each term equal to 0 and find the two values of y to get the answer.
Complete step by step solution:
Here we have been provided with the quadratic equation \[5{{y}^{2}}=30y\] and we are asked to solve it. That means we have to find the two values of y also known as the roots of the quadratic equation.
Let us use the factorization method to solve the question. But first we need to take all the terms to the L.H.S, so we get,
\[\Rightarrow 5{{y}^{2}}-30y=0\]
Since 5 is a constant so we can divide both the sides with 5 to simplify the equation,
\[\Rightarrow {{y}^{2}}-6y=0\]
Now, taking the variable y common from the two terms we get the factored form of this equation:
\[\Rightarrow y\left( y-6 \right)=0\]
Substituting each term equal to 0 we get,
\[\Rightarrow y = 0\] or $(y – 6) = 0$
\[\therefore y = 0\] or $y = 6$
Hence, the two roots of the given quadratic equation are: y = 0 or 6.
Note: You may note that this was a quadratic equation and that is why we must have obtained two roots. Here, you must not divide both the sides with the variable y otherwise one root, i.e. y = 0 would vanish and we will get only one root. In that case our answer will be considered incomplete. Here the constant term was 0 otherwise we would have used the middle term split method to get the roots.
Complete step by step solution:
Here we have been provided with the quadratic equation \[5{{y}^{2}}=30y\] and we are asked to solve it. That means we have to find the two values of y also known as the roots of the quadratic equation.
Let us use the factorization method to solve the question. But first we need to take all the terms to the L.H.S, so we get,
\[\Rightarrow 5{{y}^{2}}-30y=0\]
Since 5 is a constant so we can divide both the sides with 5 to simplify the equation,
\[\Rightarrow {{y}^{2}}-6y=0\]
Now, taking the variable y common from the two terms we get the factored form of this equation:
\[\Rightarrow y\left( y-6 \right)=0\]
Substituting each term equal to 0 we get,
\[\Rightarrow y = 0\] or $(y – 6) = 0$
\[\therefore y = 0\] or $y = 6$
Hence, the two roots of the given quadratic equation are: y = 0 or 6.
Note: You may note that this was a quadratic equation and that is why we must have obtained two roots. Here, you must not divide both the sides with the variable y otherwise one root, i.e. y = 0 would vanish and we will get only one root. In that case our answer will be considered incomplete. Here the constant term was 0 otherwise we would have used the middle term split method to get the roots.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

