How do you solve \[\tan \theta = \sqrt 3 \] ?
Answer
581.1k+ views
Hint: The question is related to the inverse trigonometry topic. Here in this question to find the value of \[\tan \theta = \sqrt 3 \] , here we use inverse to find the value of \[\theta \] . To find the exact value we use the table of trigonometry ratios for standard angles and hence find the solution for the question.
Complete step-by-step answer:
The sine, cosine, tangent, cosecant, secant and cotangent are the trigonometry ratios of trigonometry. It is abbreviated as sin, cos, tan, cosec, sec and cot. Here in this question, we have \[\tan \theta = \sqrt 3 \] . By applying the inverse to the equation we solve the equation.
To find the value we use the table of trigonometry ratios for standard angles.
The table of tangent function for standard angles is given as
Now consider the given function
\[\tan \theta = \sqrt 3 \]
So taking the inverse function we have
\[ \Rightarrow \theta = {\tan ^{ - 1}}\left( {\sqrt 3 } \right)\]
From the table of tangent function for standard angles
\[ \Rightarrow \theta = {60^ \circ }\]
This is in the form of degrees; let us convert into radians.
To convert the degree into radian we multiply the degree by \[\dfrac{\pi }{{180}}\]
Therefore, we have \[\theta = 60 \times \dfrac{\pi }{{180}}\]
On simplification we have
\[ \Rightarrow \theta = \dfrac{\pi }{3}\]
Hence, we have solved the given trigonometric function.
Therefore, the value of \[\theta \] is \[\dfrac{\pi }{3}\] in radians and the value of \[\theta \] is \[{60^ \circ }\] in degree.
So, the correct answer is “The value of \[\theta \] is \[\dfrac{\pi }{3}\] in radians and the value of \[\theta \] is \[{60^ \circ }\] in degree”.
Note: The trigonometry and inverse trigonometry are inverse for each other. The inverse of a function is represented as the arc of the function or the function is raised by the power -1. For the trigonometry and the inverse trigonometry we need to know about the table of trigonometry ratios for the standard angles. In inverse trigonometry we have to take care of the domain and range of a function as well.
Complete step-by-step answer:
The sine, cosine, tangent, cosecant, secant and cotangent are the trigonometry ratios of trigonometry. It is abbreviated as sin, cos, tan, cosec, sec and cot. Here in this question, we have \[\tan \theta = \sqrt 3 \] . By applying the inverse to the equation we solve the equation.
To find the value we use the table of trigonometry ratios for standard angles.
The table of tangent function for standard angles is given as
| Angle | 0 | 30 | 45 | 60 | 90 |
| tan | 0 | \[\dfrac{1}{{\sqrt 3 }}\] | \[1\] | \[\sqrt 3 \] | 1 |
Now consider the given function
\[\tan \theta = \sqrt 3 \]
So taking the inverse function we have
\[ \Rightarrow \theta = {\tan ^{ - 1}}\left( {\sqrt 3 } \right)\]
From the table of tangent function for standard angles
\[ \Rightarrow \theta = {60^ \circ }\]
This is in the form of degrees; let us convert into radians.
To convert the degree into radian we multiply the degree by \[\dfrac{\pi }{{180}}\]
Therefore, we have \[\theta = 60 \times \dfrac{\pi }{{180}}\]
On simplification we have
\[ \Rightarrow \theta = \dfrac{\pi }{3}\]
Hence, we have solved the given trigonometric function.
Therefore, the value of \[\theta \] is \[\dfrac{\pi }{3}\] in radians and the value of \[\theta \] is \[{60^ \circ }\] in degree.
So, the correct answer is “The value of \[\theta \] is \[\dfrac{\pi }{3}\] in radians and the value of \[\theta \] is \[{60^ \circ }\] in degree”.
Note: The trigonometry and inverse trigonometry are inverse for each other. The inverse of a function is represented as the arc of the function or the function is raised by the power -1. For the trigonometry and the inverse trigonometry we need to know about the table of trigonometry ratios for the standard angles. In inverse trigonometry we have to take care of the domain and range of a function as well.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

