Answer
Verified
385.5k+ views
Hint: In this particular question we need to use basic logarithmic properties to simplify the equation. Then we need to further solve the equation and get the desired answer.
Complete step by step solution:
In the above question, it is given that,
$\log x + \log (x - 3) = 1$
(Since $\log a + \log b = \log (ab)$ )
Using the above stated property we get,
$ \Rightarrow \log (x(x - 3)) = 1$
Taking antilog on both sides of the equation we get,
$ \Rightarrow anti\log (\log (x(x - 3))) = anti\log 1$
$ \Rightarrow x(x - 3) = {10^1}$
On solving the above equation we get a quadratic equation
$ \Rightarrow {x^2} - 3x = 10$
Subtracting 10 from both sides of the equation
$ \Rightarrow {x^2} - 3x - 10 = 0$
Now solve the above quadratic equation for x
$ \Rightarrow {x^2} - 5x + 2x - 10 = 0$
$ \Rightarrow x(x - 5) + 2(x - 5) = 0$
$ \Rightarrow (x + 2)(x - 5) = 0$
This implies that either $x = - 2$or $x = 5$
As log can not be a negative value therefore the $x = - 2$ is rejected and hence $x = 5$ is the required solution to the above logarithmic equation.
Note:
Remember to recall the basic logarithmic properties to solve the above question. Note that
$
\log x = 1 \\
\Rightarrow x = {10^1} \\
\Rightarrow x = 10 \\
$
The basic logarithmic algebra includes the following properties:
$
\log a + \log b = \log (ab) \\
\log a - \log b = \log \left( {\dfrac{a}{b}} \right) \\
\log {a^b} = b\log a \\
{\log _a}a = 1 \\
$
Complete step by step solution:
In the above question, it is given that,
$\log x + \log (x - 3) = 1$
(Since $\log a + \log b = \log (ab)$ )
Using the above stated property we get,
$ \Rightarrow \log (x(x - 3)) = 1$
Taking antilog on both sides of the equation we get,
$ \Rightarrow anti\log (\log (x(x - 3))) = anti\log 1$
$ \Rightarrow x(x - 3) = {10^1}$
On solving the above equation we get a quadratic equation
$ \Rightarrow {x^2} - 3x = 10$
Subtracting 10 from both sides of the equation
$ \Rightarrow {x^2} - 3x - 10 = 0$
Now solve the above quadratic equation for x
$ \Rightarrow {x^2} - 5x + 2x - 10 = 0$
$ \Rightarrow x(x - 5) + 2(x - 5) = 0$
$ \Rightarrow (x + 2)(x - 5) = 0$
This implies that either $x = - 2$or $x = 5$
As log can not be a negative value therefore the $x = - 2$ is rejected and hence $x = 5$ is the required solution to the above logarithmic equation.
Note:
Remember to recall the basic logarithmic properties to solve the above question. Note that
$
\log x = 1 \\
\Rightarrow x = {10^1} \\
\Rightarrow x = 10 \\
$
The basic logarithmic algebra includes the following properties:
$
\log a + \log b = \log (ab) \\
\log a - \log b = \log \left( {\dfrac{a}{b}} \right) \\
\log {a^b} = b\log a \\
{\log _a}a = 1 \\
$
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Why Are Noble Gases NonReactive class 11 chemistry CBSE
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
At which age domestication of animals started A Neolithic class 11 social science CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Write a letter to the principal requesting him to grant class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE