
How do you solve $\left| {5x - 4} \right| = 6$ ?
Answer
546.9k+ views
Hint: The above given equation is an example of absolute value equation. Absolute value equations are the equations where the variable is within an absolute value operator, also known as a modulus operator. So, while considering an absolute value equation involving variables we have to consider both the cases of positive and negative signs.
Complete step-by-step solution:
Given
$\left| {5x - 4} \right| = 6.................(1)$
Now in order to solve the given equation we need to solve for $x$ .
Such that we have to manipulate the given equation in terms of only $x$ , which can be achieved by
performing different arithmetic operations on both LHS and RHS equally.
Now on observing $(1)$ we can say that in the LHS there is the involvement of absolute or the modulus sign. Such that in order to solve for $x$ we have to remove the absolute or the modulus sign. Now to remove the modulus sign we have to take two cases of both positive and negative signs.
So, we can write $(1)$ as:
$
\Rightarrow \left| {5x - 4} \right| = 6 \\
\Rightarrow 5x - 4 = \pm 6..........(2) \\
$
Now on observing $(2)$ we can say there are two cases such that we have to take both the cases and solve them separately:
$ \Rightarrow 5x - 4 = \pm 6$
$ \Rightarrow 5x - 4 = 6$ and $5x - 4 = - 6$
$ \Rightarrow 5x = 10$ and $5x = - 2$
$ \Rightarrow x = 2$ and $x = \dfrac{{ - 2}}{5}$
Therefore, on solving $\left| {5x - 4} \right| = 6$ we get $x = 2$ and $x = \dfrac{{ - 2}}{5}$ .
Note: The equation is said to be true when only if we find the value of the variable which makes the equation true. We can also check if the value of the variable that we got is true or not by substituting the value of the variable back into the equation and checking whether it satisfies the given equation or not.
Complete step-by-step solution:
Given
$\left| {5x - 4} \right| = 6.................(1)$
Now in order to solve the given equation we need to solve for $x$ .
Such that we have to manipulate the given equation in terms of only $x$ , which can be achieved by
performing different arithmetic operations on both LHS and RHS equally.
Now on observing $(1)$ we can say that in the LHS there is the involvement of absolute or the modulus sign. Such that in order to solve for $x$ we have to remove the absolute or the modulus sign. Now to remove the modulus sign we have to take two cases of both positive and negative signs.
So, we can write $(1)$ as:
$
\Rightarrow \left| {5x - 4} \right| = 6 \\
\Rightarrow 5x - 4 = \pm 6..........(2) \\
$
Now on observing $(2)$ we can say there are two cases such that we have to take both the cases and solve them separately:
$ \Rightarrow 5x - 4 = \pm 6$
$ \Rightarrow 5x - 4 = 6$ and $5x - 4 = - 6$
$ \Rightarrow 5x = 10$ and $5x = - 2$
$ \Rightarrow x = 2$ and $x = \dfrac{{ - 2}}{5}$
Therefore, on solving $\left| {5x - 4} \right| = 6$ we get $x = 2$ and $x = \dfrac{{ - 2}}{5}$ .
Note: The equation is said to be true when only if we find the value of the variable which makes the equation true. We can also check if the value of the variable that we got is true or not by substituting the value of the variable back into the equation and checking whether it satisfies the given equation or not.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

