
How do you solve for \[x\] in \[C=b-bx\]?
Answer
538.8k+ views
Hint: From the given question we have been asked to find the value of \[x\] from a given equation. So, for solving this question we will use the basic operation in mathematics that is division, multiplication, addition and subtraction and simplify the given equation further and solve the given question. We will proceed with our solution as follows.
Complete step by step solution:
We are given that the equation is \[C=b-bx\].
So, for this equation we will now simplify as follows.
For the above equation we will send the term on the left hand side to the right hand side of the equation and also we will send the variable term on the right hand side to the left hand side of the equation.
So, the equation will be reduced as follows.
\[\Rightarrow C=b-bx\]
\[\Rightarrow bx=b-C\]
Now we will use the basic operation in mathematics which is division and we will divide with b on the both sides of the equation. So, we get the equation reduced as follows.
\[\Rightarrow \dfrac{bx}{b}=\dfrac{b-C}{b}\]
Now we will cancel the same term which is present in the numerator and denominator on the left hand side of the equation. So, we get the equation reduced as follows.
\[\Rightarrow x=\dfrac{b-C}{b}\]
Therefore the solution to the given question is \[x=\dfrac{b-C}{b}\].
Note: Students must not do calculation mistakes in solving the problem. We must have good knowledge in the basic mathematical operations like division to solve this problem. We must not do and simplification mistakes for example if we write the term as
\[\Rightarrow bx=C-b\] instead of \[\Rightarrow bx=b-C\] then our solution will be wrong.
Complete step by step solution:
We are given that the equation is \[C=b-bx\].
So, for this equation we will now simplify as follows.
For the above equation we will send the term on the left hand side to the right hand side of the equation and also we will send the variable term on the right hand side to the left hand side of the equation.
So, the equation will be reduced as follows.
\[\Rightarrow C=b-bx\]
\[\Rightarrow bx=b-C\]
Now we will use the basic operation in mathematics which is division and we will divide with b on the both sides of the equation. So, we get the equation reduced as follows.
\[\Rightarrow \dfrac{bx}{b}=\dfrac{b-C}{b}\]
Now we will cancel the same term which is present in the numerator and denominator on the left hand side of the equation. So, we get the equation reduced as follows.
\[\Rightarrow x=\dfrac{b-C}{b}\]
Therefore the solution to the given question is \[x=\dfrac{b-C}{b}\].
Note: Students must not do calculation mistakes in solving the problem. We must have good knowledge in the basic mathematical operations like division to solve this problem. We must not do and simplification mistakes for example if we write the term as
\[\Rightarrow bx=C-b\] instead of \[\Rightarrow bx=b-C\] then our solution will be wrong.
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