
How do you solve for \[h\] in \[a = ch + f\] ?
Answer
550.2k+ views
Hint: In this problem to solve for \[h\] means to express the given equation in the form of \[h\] such that it gives the value of \[h\] . Right now in the given condition it is in the form of \[a\] . We will have to separate the term \[h\] from the remaining terms by rearranging other letters or variables of the equation we can say.
Complete step by step solution:
Given the equation is \[a = ch + f\]
Now very first we will shift \[f\] to the other side of the equation.
\[a - f = ch\]
But in this situation \[h\] is in product with \[c\] . So we will take \[c\] on the other side of the equation such that it is in division.
\[\dfrac{{a - f}}{c} = h\]
Now this is our equation but we will take \[h\] on LHS such that we will get it in \[h\] form.
\[ \Rightarrow h = \dfrac{{a - f}}{c}\]
This is our answer.
So, the correct answer is “$h = \dfrac{{a - f}}{c}$”.
Note: Note that solve for \[h\] means just express the equation in the form of \[h\] . Now if we are given with values of \[a,c,f\] we can get the value of \[h\] . Since we want only \[h\] on LHS we shifted all other letters on RHS. if the same process needs to be done with \[c\] we will shift all letters except \[c\] to the other side.
Equations of conversion are written in this pattern like of temperature, weight, distance etc.
Complete step by step solution:
Given the equation is \[a = ch + f\]
Now very first we will shift \[f\] to the other side of the equation.
\[a - f = ch\]
But in this situation \[h\] is in product with \[c\] . So we will take \[c\] on the other side of the equation such that it is in division.
\[\dfrac{{a - f}}{c} = h\]
Now this is our equation but we will take \[h\] on LHS such that we will get it in \[h\] form.
\[ \Rightarrow h = \dfrac{{a - f}}{c}\]
This is our answer.
So, the correct answer is “$h = \dfrac{{a - f}}{c}$”.
Note: Note that solve for \[h\] means just express the equation in the form of \[h\] . Now if we are given with values of \[a,c,f\] we can get the value of \[h\] . Since we want only \[h\] on LHS we shifted all other letters on RHS. if the same process needs to be done with \[c\] we will shift all letters except \[c\] to the other side.
Equations of conversion are written in this pattern like of temperature, weight, distance etc.
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