Question

How do you solve for a in $ 5 + ab = c $ ?

Answer 1

Hint: We need to find the value of a in this question. To solve this question, we are going to arrange on one side of the "equal to" sign and all the other terms on the other side of the "equal to" sign. For doing this, we will need to perform simple calculations on both sides of the "equal to" sign.

Complete step by step solution:
In this question, we are given an equation
 $ \Rightarrow 5 + ab = c $ - - - - - - - - (1)
And we need to find the value of a for this equation.
 For finding the value of a, we need to arrange a on one side of "equal to" sign and all other terms on the other side of "equal to" sign.
First of all, subtract 5 on both sides of the equation. We get,
 $
   \Rightarrow 5 + ab - 5 = c - 5 \\
   \Rightarrow 5 - 5 + ab = c - 5 \;
  $
 $ \Rightarrow ab = c - 5 $ - - - - - - - - (2)
Now we need to take b on the other side of the "equal to" sign. For that we are going to divide the equation (2) with b on both sides of "equal to" sign.
Dividing by b, we get
 $ \Rightarrow \dfrac{{ab}}{b} = \dfrac{{c - 5}}{b} $ - - - - - - - - - (3)
Here, in the above equation, b gets cancelled from both denominator and numerator on the left side of "equal to" sign.
So, equation (3) becomes,
 $ \Rightarrow a = \dfrac{{c - 5}}{b} $
Therefore, we have arranged on one side of the "equal to" sign and all the other terms on the other side of the "equal to" sign.
Hence, our answer is $ a = \dfrac{{c - 5}}{b} $ .
So, the correct answer is “ $ a = \dfrac{{c - 5}}{b} $ ”.

Note: In any given equation, the terms on the left side of “equals to” sign are said to be on LHS (Left hand side) and the terms on the right side of the “equals to” sign are said to be on RHS (Right hand side).
Keep in mind that LHS has to always be equal to RHS.