
How do you solve \[\dfrac{x}{5} = 10\]?
Answer
534k+ views
Hint: In the given problem we need to solve this for ‘x’. We can solve this using the transposition method. The common transposition method is to do the same thing (mathematically) to both sides of the equation, with the aim of bringing like terms together and isolating the variable (or the unknown quantity). That is we group the ‘x’ terms one side and constants on the other side of the equation.
Complete step-by-step solution:
Given, \[\dfrac{x}{5} = 10\].
We transpose ‘5’ which is present in the left hand side of the equation to the right hand side of the equation by multiplying ‘5’ on the right hand side of the equation.
\[ \Rightarrow x = 10 \times 5\]
We have separated the variable and the constant terms separately and we can solve for ‘x’
\[ \Rightarrow x = 50\].This is the required answer.
Thus the required answer is x = 50.
Note: We can check whether the obtained solution is correct or wrong. All we need to do is substituting the value of ‘x’ in the given problem.
\[ \Rightarrow \dfrac{x}{5} = 10\]
\[ \Rightarrow \dfrac{{50}}{5} = 10\]
\[ \Rightarrow 10 = 10\].
That is LHS=RHS. Hence the obtained is correct.
In the above we did the transpose of addition and subtraction. Similarly if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Complete step-by-step solution:
Given, \[\dfrac{x}{5} = 10\].
We transpose ‘5’ which is present in the left hand side of the equation to the right hand side of the equation by multiplying ‘5’ on the right hand side of the equation.
\[ \Rightarrow x = 10 \times 5\]
We have separated the variable and the constant terms separately and we can solve for ‘x’
\[ \Rightarrow x = 50\].This is the required answer.
Thus the required answer is x = 50.
Note: We can check whether the obtained solution is correct or wrong. All we need to do is substituting the value of ‘x’ in the given problem.
\[ \Rightarrow \dfrac{x}{5} = 10\]
\[ \Rightarrow \dfrac{{50}}{5} = 10\]
\[ \Rightarrow 10 = 10\].
That is LHS=RHS. Hence the obtained is correct.
In the above we did the transpose of addition and subtraction. Similarly if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Convert 40circ C to Fahrenheit A 104circ F B 107circ class 8 maths CBSE

Advantages and disadvantages of science

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE


